Can you apply logarithm rules for base e as well?

poppjngcandy

I’m pretty sure this is a stupid question but I’m still confused…

Reply 1

mqb2766

yes, the natural logarithm (base e) is the "usual" log.

Reply 2

poppjngcandy

Original post by mqb2766

yes, the natural logarithm (base e) is the "usual" log.

thank you! so for example i could say that e^2x + e^3x is the same as (e^2x)^3x ?

Reply 3

mqb2766

Original post by poppjngcandy

thank you! so for example i could say that e^2x + e^3x is the same as (e^2x)^3x ?

There no log there and your exponent rules are wrong.
https://www.mathsisfun.com/algebra/exponent-laws.html
Probably best to post the original quesiton and your working.

Reply 4

22gz

Original post by poppjngcandy

thank you! so for example i could say that e^2x + e^3x is the same as (e^2x)^3x ?

No you couldn’t, e^x is just like any other power, like 2²+2³ doesn’t equal (2²)³

Reply 5

poppjngcandy

Original post by 22gz

No you couldn’t, e^x is just like any other power, like 2²+2³ doesn’t equal (2²)³

oh yeah 😭 so the normal multiplication and division rules for log e and ln wouldn’t apply at all? sorry im not great with this topic ;(

Reply 6

mqb2766

Original post by poppjngcandy

oh yeah 😭 so the normal multiplication and division rules for log e and ln wouldn’t apply at all? sorry im not great with this topic ;(

you can factorise the original expression if you want
e^2x + e^3x = e^(2x) (1 + e^x)
but thats about it. Similarly
(e^2x)^3x = e^(6x^2)
as in the previous link.

(edited 10 months ago)

Reply 7

poppjngcandy

Original post by mqb2766

you can factorise the original expression if you want
e^2x + e^3x = e^(2x) (1 + e^x)
but thats about it. Similarly
(e^2x)^3x = e^(6x^2)
as in the previous link.

thanks!!