electricity mcq plz help

it's from the CGP book.
basically, V = 160
E = 120kJ
t = 60s
and we need to find the current (I), flowing through the electric heater.
the answer is 12.5A

does anyone have any ideas on how to connect I with another variable given here?

Reply 1

Joinedup

Power (Watts) is Energy (Joules) per unit of time (seconds)

Power is also PD (Volts) multiplied by current (Amps)

Reply 2

humandizaster000

Original post by Joinedup

Power (Watts) is Energy (Joules) per unit of time (seconds)

Power is also PD (Volts) multiplied by current (Amps)

Hang on a sec.
If P=Et (according to formula sheet),
you're saying that IV=Et (I think)
so 120/160 x 60 x10^3 would be the same as 0.75 x 60 x 10^3, which is 45 x 10^3 A.
This isn't an option.