https://www.quora.com/profile/Bravewarrior/p-147225613

Here is the question and its solution.Can anyone please explain the solution to part a? Thanks!

Here is the question and its solution.Can anyone please explain the solution to part a? Thanks!

Original post by pigeonwarrior

https://www.quora.com/profile/Bravewarrior/p-147225613

Here is the question and its solution.Can anyone please explain the solution to part a? Thanks!

Here is the question and its solution.Can anyone please explain the solution to part a? Thanks!

What is the range of y(t)? So if the horizontal line y=k intersects it, what range can k be?

Original post by mqb2766

What is the range of y(t)? So if the horizontal line y=k intersects it, what range can k be?

For y(t) the range would be -1<y<1 and I guess if y=k intersects it then it becomes k=cos2t+1 but how would the horizontal line affect the range?

Original post by pigeonwarrior

For y(t) the range would be -1<y<1 and I guess if y=k intersects it then it becomes k=cos2t+1 but how would the horizontal line affect the range?

cos(2t) has a range -1 to 1, but

cos(2t) + 1 has a range 0 to 2

So if the horizontal line y=k intersects the curve, then k must have the same range 0 to 2 as the horizontal line y=3 say would be too high and the horizontal line y=-1 would be too low.

Original post by mqb2766

cos(2t) has a range -1 to 1, but

cos(2t) + 1 has a range 0 to 2

So if the horizontal line y=k intersects the curve, then k must have the same range 0 to 2 as the horizontal line y=3 say would be too high and the horizontal line y=-1 would be too low.

cos(2t) + 1 has a range 0 to 2

So if the horizontal line y=k intersects the curve, then k must have the same range 0 to 2 as the horizontal line y=3 say would be too high and the horizontal line y=-1 would be too low.

Ohhh yes i did not think of this 😬 thank you so much!

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