When an aqueous solution of chlorate(I) ions (CIO-) is reduced, chloride ions and hydroxide ions are formed. Write a half equation to represent this change. Please help! I have ClO- --> Cl- + OH- but I dont understand how to balance it
When an aqueous solution of chlorate(I) ions (CIO-) is reduced, chloride ions and hydroxide ions are formed. Write a half equation to represent this change. Please help! I have ClO- --> Cl- + OH- but I dont understand how to balance it
Everything is balanced apart from H. So you have to add H+ ions to the other side. Then balance charges using e-
I found an answer but i don't understand how it came about. ClO- + H2O + 2e- ---> Cl- + 2OH-
Balancing half-equations in acidic medium you are only allowed to use hydrogen ions, water and electrons. In basic medium you are only allowed to use water, hydroxide ions and electrons.
"When an aqueous solution of chlorate(I) ions (CIO-) is reduced, chloride ions and hydroxide ions are formed"
ClO- ==> Cl- + OH-
You need water on the left hand side (LHS) for hydrogen. To compensate for the extra oxygen on RHS double the OH-