yh i meant ii, thanks for that, could you help me with part B ii tho aswell, i know we need to use s=ut + 1/2at^2 but im confused as to how the mark scheme in order to find the distance for B used that equation with two different t values, this is what they wrote: Distance moved by B = (1/2x1.5x162 ) + 24(t – 16), how can you use two different t values?
(b) Cars A and B are now on a straight road with car A moving at 22 m s–1 and car B at rest. As car A passes car B, car B accelerates from rest in the same direction at 1.5 m s –2 for 16 s. It then moves with constant velocity. Fig. 16.2 shows the graph of velocity against time for car A. The time t = 0 is taken when the cars are alongside. Fig. 16.2 (i) Sketch the graph of velocity against time for car B on Fig. 16.2. [2]
(ii) Determine the time taken for car B to be alongside car A.