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    A little something my teacher asked me to solve a couple of weeks ago. The aim is to find the next two lines of the triangle. Its quite interesting and definetely made me think.

    And the first person to do this will recieve the beloved rep tomorrow.
    Enjoy!!
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    What the hell are you on about?
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    pimping triangle there
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    Do we have to be on acid to work it out?
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    damn...the attatchement didn't work
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    I'm stuck working out the first line... O.o
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    (Original post by zafaru123)
    A little something my teacher asked me to solve a couple of weeks ago.
    Can't your teacher solve the problems himself without getting others to solve them?
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    (Original post by aphirst)
    I'm stuck working out the first line... O.o
    I think you have to use imaginary numbers to solve imaginary problems.
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    lol...firstly, the acid is not required...and i don't why she asked me...but only one teacher in our whole maths department got it
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    this: triangle
    http://upload.wikimedia.org/wikipedi...-acute.svg.png

    this: not a triangle
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    its triangle-shaped
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    1/7 1/42 1/105 1/140 1/105 1/42 1/7

    1/8 1/56 1/168 1/280 1/280 1/168 1/56 1/8

    Hope there's no numerical slips, as I couldn't be bothered to go and find a calculator
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    If it's "triangle shaped" and we have to find the "next two lines"..... wtf are we meant to be doing? :p:
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    (Original post by tommm)
    Spoiler:
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    1/7 1/42 1/105 1/140 1/105 1/42 1/7

    1/8 1/56 1/168 1/280 1/280 1/168 1/56 1/8

    Hope there's no numerical slips, as I couldn't be bothered to go and find a calculator
    and we have a winner...you solved it a minute quicker then me lol...will rep you tomorrow.
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    (Original post by heflob)
    1/7 1/42 1/210 1/840 1/210 1/42 1/7

    1/8 1/56 1/336 1/1680 1/1680 1/336 1/56 1/8

    As far as I can tell

    Did I win?
    the outer bits are correct, but not the inner ones
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    The 1/30 looked pretty random to me. I suppose there is a pattern?
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    may i ask tomm...what method did you use
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    If you can't spot the pattern:

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    Add up any two adjacent fractions. What do you get?
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    yes theres a pattern, take the first two lines for example. 1/2 add a 1/2=1/1. the number above of them. so 1/3 add a 1/6=1/2 (the number above the two fractions)
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    (Original post by zafaru123)
    may i ask tomm...what method did you use
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    A fraction (let's call it A) and the two fractions below it (B and C) are related by A = B + C. We can rearrange this to find that C = A - B, and I just did this for every fraction.
 
 
 
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