further mechanics impulse question
A particle P of mass 0.5 kg is moving in a straight line with speed 2.8 m s–1 when it receives
an impulse of magnitude 3 N s.
The angle between the direction of motion of P immediately before receiving the impulse and
the line of action of the impulse is α, where tan α = 4/3, as shown in Figure 2.
Find the speed of P immediately after receiving the impulse.
How would I go about solving this? I'm completely stuck
an impulse of magnitude 3 N s.
The angle between the direction of motion of P immediately before receiving the impulse and
the line of action of the impulse is α, where tan α = 4/3, as shown in Figure 2.
Find the speed of P immediately after receiving the impulse.
How would I go about solving this? I'm completely stuck
Use trig to calculate the new velocity in the parallel and perpendicular directions and then combine using pythagoras or draw a triangle with two sides repesenting the change in velocity (scaled impulse) and the original velocity, so the third gives the new velocity.
(edited 8 months ago)
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