Well let's say we have the combustion of methane:
CH4+2O2−>CO2+2H2OFrom the equation we see that 1 mole of methane reacts with 2 moles of oxygen which then produces 1 mole of carbon dioxide and 2 moles of water.
If we had 16g of methane we would require 64g of oxygen to produce 48g of
CO2 and 36g of water
But if we had 4g of methane we would require 16g of oxygen to produce 12g of
CO2 and 9g of water
All i've done is divide all values by 4
Hopefully this explanation is what you are after