Year 12s: what will be the first way you research your future options? >>

Simplifying Arrhenius Equation

help!!!,

I understand that you use logs but im unsure how you get from;

k = Ae^-Ea/RT to lnk=lnA-Ea/RT

THANKS GUYS!

help!!!... I think Im getting rusty on logs (or i may not have the coorect understanding)

I understand that you use logs but im unsure how you get from;

k = Ae^-Ea/RT to lnk=lnA-Ea/RT

THANKS GUYS!

Reply 2

charco

Study Forum Helper

Original post by oranjuice

help!!!,

I understand that you use logs but im unsure how you get from;

k = Ae^-Ea/RT to lnk=lnA-Ea/RT

THANKS GUYS!

You take logs to base e (natural logs)

Reply 3

username1094137

Like Charco said you take natural logs of both sides. So lnE^a/RT, the ln and e cancel so a/RT is left.

Reply 4

TSR Learn Together

Official Rep

Hi there,

While you're waiting for an answer, did you know we have 300,000 study resources that could answer your question in TSR's Learn together section?

We have everything from Teacher Marked Essays to Mindmaps and Quizzes to help you with your work. Take a look around.

If you're stuck on how to get started, try creating some resources. It's free to do and can help breakdown tough topics into manageable chunks. Get creating now.

Thanks!

Not sure what all of this is about? Head here to find out more.

Reply 5

Borek

Original post by oranjuice

help!!!... I think Im getting rusty on logs (or i may not have the coorect understanding)

I understand that you use logs but im unsure how you get from;

k = Ae^-Ea/RT to lnk=lnA-Ea/RT

THANKS GUYS!