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M1 Help! Urgent!!!

I am absolutely terrible at M1... Please explain this as well as you can.

Question: A plane flies due north at 300kmh^-1 but a crosswind blows north-east at 40kmh^-1. Find the resultant velocity of the plane and its bearing (to the nearest degree).


HEEEELP! :frown:
draw a picture... first line going north length 300,

second line going northeast starting at the top of the other line length 40. the third side of the triangle gives you the answer.
Reply 2
Original post by the bear
draw a picture... first line going north length 300,

second line going northeast starting at the top of the other line length 40. the third side of the triangle gives you the answer.


That seemed to be the logical approach from my point of view (assuming that you are basically talking about pythogoras, right?)
So I did it and I got 302.65 (2dp) answer, but my teacher's answer states that it should be 329.5... Am I missing something or is his answers wrong?
Original post by saule1116
That seemed to be the logical approach from my point of view (assuming that you are basically talking about pythogoras, right?)
So I did it and I got 302.65 (2dp) answer, but my teacher's answer states that it should be 329.5... Am I missing something or is his answers wrong?


it won't be a 90° triangle so Pythagoras won't be much use.
Reply 4
Original post by the bear
it won't be a 90° triangle so Pythagoras won't be much use.


Oooohhhhhh.....

So... That's because the crosswind is north-east, right?
So do I use Sine rule/Cosine rule to solve this? I don't know any angles.. :/
Original post by saule1116
Oooohhhhhh.....

So... That's because the crosswind is north-east, right?
So do I use Sine rule/Cosine rule to solve this? I don't know any angles.. :/


mwhahaha but you do know an angle... north-east is a particular angle direction ?
Reply 6
Original post by the bear
mwhahaha but you do know an angle... north-east is a particular angle direction ?


..is that 45 degrees? :curious: (I don't know what I was thinking when I picked maths. xD All I can do is algebra. :biggrin: )
Original post by saule1116
..is that 45 degrees? :curious: (I don't know what I was thinking when I picked maths. xD All I can do is algebra. :biggrin: )


Yeah 45 degrees :smile:
Reply 8
Original post by iscribbletoomuch
Yeah 45 degrees :smile:


Woop woop! I'll give that part another shot :biggrin:
Reply 9
Original post by iscribbletoomuch
Yeah 45 degrees :smile:


I got 273.18 (2dp), this still doesn't match my teacher's answer! :frown: I used the Cosine rule.
Oh you are using 45 degrees as your angle, you should use 135 degrees!
Reply 11
Original post by iscribbletoomuch
Can you post your working?


R^2=300^2+40^2-2x300x40xcos45(degrees)
Original post by saule1116
R^2=300^2+40^2-2x300x40xcos45(degrees)


Basically, 45 degrees isn't the angle to use, you should use 180-45 since the vectors effectively stack up
(edited 8 years ago)
Reply 13
Original post by iscribbletoomuch
Basically, 45 degrees isn't the angle to use, you should use 180-45 since the vectors effectively stack up


THANK YOU SO MUCH!!!!! (I would share my cookies with you!)
It works! That's almost like magic! Yay! :biggrin:
Thank you! ^^
Original post by saule1116
THANK YOU SO MUCH!!!!! (I would share my cookies with you!)
It works! That's almost like magic! Yay! :biggrin:
Thank you! ^^


I do like cookies :biggrin:
Maybe it is magic :wink:

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