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Find general solution for differential equation

TSRforum

Sin(y)cos(x) dy/dx = (x)cos(y)/cos(x)

Here is my working out so far:

Reply 1

TeeEm

Original post by TSRforum

Sin(y)cos(x) dy/dx = (x)cos(y)/cos(x)

Here is my working out so far:

integration by parts in the RHS

Reply 2

TSRforum

What about cos(y)sin(2x) dy/dx = cot(x)cosec(y) ? I got sin(y)cos(y) dy = 1/2cosecx^2 dx is this correct? I cant seem to integrate the dy part

Posted from TSR Mobile

(edited 8 years ago)

Reply 3

Louisb19

Original post by TSRforum

Sin(y)cos(x) dy/dx = (x)cos(y)/cos(x)

Here is my working out so far:

By parts and then using inspection to solve that integral. The following may help you:

\dfrac{\mathrm{d}}{\mathrm{d}x} \tan^2x = 2 \tan{x} \sec^2x

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Find general solution for differential equation

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