3(2c – 5) – 2(c – 4)

Are you missing an equals sign?

Can someone explain this to me?

3(2c - 5) - 2(c - 4)

i'm assuming there is no equal, basically all you do is factorise it, so..

3(2c - 5)
3 x 2c = 6c
3 x -5 = -15

so: 6c - 15
**don't forget to use the -/+ rule**

now,
2(c - 4) ** do not use -2 as that isn't to do with equation, if it was --2(2c - 4) that would be different**
once again, time them.

2 x c = 2c
2 x -4 = -8

2c - 8

now bring them together...
6c - 15 + 2c - 8

now deal with them in groups.

6c + 2c = 8c
-15 - 8 = -23.

So answer is... 8c - 23.

Can someone explain this to me?

3(2c - 5) - 2(c - 4)

Now,
2(c - 4) ** do not use -2 as that isn't to do with equation, if it was --2(2c - 4) that would be different**
Once again, time them..

3(2c - 5) - 2(c - 4)

I'm assuming there is no equal, basically all you do is factorise it, so..

3(2c - 5)
3 x 2c = 6c
3 x -5 = -15

So: 6c - 15
**Don't forget to use the -/+ rule**

Now,
2(c - 4) ** do not use -2 as that isn't to do with equation, if it was --2(2c - 4) that would be different**
Once again, time them.

2 x c = 2c
2 x -4 = -8

2c - 8

Now bring them together...
6c - 15 + 2c - 8

Now deal with them in groups.

6c + 2c = 8c
-15 - 8 = -23.

So answer is... 8c - 23.

Can someone explain this to me?

Lol you just did his homework


Posted from TSR Mobile

But it is -2(2c - 4)

Lol you just did his homework


Posted from TSR Mobile

Since when did homework assignments consist of one question?

3(2c - 5) - 2(c - 4)

I'm assuming there is no equal, basically all you do is factorise it, so..

3(2c - 5)
3 x 2c = 6c
3 x -5 = -15

So: 6c - 15
**Don't forget to use the -/+ rule**

Now,
2(c - 4) ** do not use -2 as that isn't to do with equation, if it was --2(2c - 4) that would be different**
Once again, time them.

2 x c = 2c
2 x -4 = -8

2c - 8

Now bring them together...
6c - 15 + 2c - 8

Now deal with them in groups.

6c + 2c = 8c
-15 - 8 = -23.

So answer is... 8c - 23.

3(2c - 5) - 2(c - 4)

So answer is... 8c - 23.

This is incorrect, the answer is 4c-7

Exactly what I got.

(Original post by ckfeister)
3(2c - 5) - 2(c - 4)

Now,
2(c - 4) ** do not use -2 as that isn't to do with equation, if it was --2(2c - 4) that would be different**

But it is -2(2c - 4)

(Original post by B_9710)
This is incorrect, the answer is 4c-7


So did I. As in my earlier post

But ckfeister seems to have lost the plot since.
Seems to think it is OK to ignore the minus sign.
So not only did he do the guy's homework.
He actually did it wrong