When drawing the 3 isomers Position- just change the double bond so it's on a different carbon Functional group - change it from an alkene to n alkane, remove the double c bond What about for chain isomerism?
When drawing the 3 isomers Position- just change the double bond so it's on a different carbon Functional group - change it from an alkene to n alkane, remove the double c bond What about for chain isomerism?
What was the bond angles for SF4? I know the shape, I put 117.5 and 87.5 for bond angles because you minus 2.5 per line pair. But I'm not sure if you do it for both bond angles of it you split it between them .
For the Shapes of Molecules qs, SF4 has 4 bonding pairs and 1 lone pair - take the assumption that you took a trigonal bipyramidal but then put a lone pair on it, the bond angles on the trigonal bipyramidal is 90, 120 degrees and its cut by 2/2.5° so you should take 88 and 118°
What was the bond angles for SF4? I know the shape, I put 117.5 and 87.5 for bond angles because you minus 2.5 per line pair. But I'm not sure if you do it for both bond angles of it you split it between them .
its 90 as its a trigonal bypyramid and the lone pair is opposite the T shape or maybe 120
Also dos anyone get oxygen for that which element ionisation number thing? I can't remember is it was period 3 or 2 and I'm shitting myself in case it's sulphur instead, as it was the 7th ionisation energy right?
When drawing the 3 isomers Position- just change the double bond so it's on a different Carbon Functional group - change it from an alkene to n alkane, remove the double c bond What about for chain isomerism?
For functional group it has to be cyclobutane and yeah for chain it's methylpropene
When drawing the 3 isomers Position- just change the double bond so it's on a different carbon Functional group - change it from an alkene to n alkane, remove the double c bond What about for chain isomerism?
For the Shapes of Molecules qs, SF4 has 4 bonding pairs and 1 lone pair - take the assumption that you took a trigonal bipyramidal but then put a lone pair on it, the bond angles on the trigonal bipyramidal is 90, 120 degrees and its cut by 2/2.5° so you should take 88 and 118°
So....I got it right? yay! I wasn't sure because I know the shape and it only had one electron pair, but I didn't know if it affected both angles by 2.5/2.