The Student Room Group

chemistry transition metals

http://filestore.aqa.org.uk/subjects/AQA-CHEM5-QP-JAN12.PDF

could somone pls help me understand the equation in q8 part ii about the complex standing in air ????? thanks !!!
Original post by HG1
http://filestore.aqa.org.uk/subjects/AQA-CHEM5-QP-JAN12.PDF

could somone pls help me understand the equation in q8 part ii about the complex standing in air ????? thanks !!!



Have you looked at the mark scheme? What don't you understand?
Reply 2
Avatar for HG1
HG1
OP
Original post by TeachChemistry
Have you looked at the mark scheme? What don't you understand?



yeah the mark scheme gives this 4(NH2CH2CH2NH2)3 (2+) + O2 + 2H2O GIVES 4(NH2CH2H2NH2)3 (3+) + 4OH-

I just dont understand how you go about constructing the equation ?
Original post by HG1
yeah the mark scheme gives this 4(NH2CH2CH2NH2)3 (2+) + O2 + 2H2O GIVES 4(NH2CH2H2NH2)3 (3+) + 4OH-

I just dont understand how you go about constructing the equation ?



You've missed the cobalt off but no matter.

Write a half equation for cobalt oxidation from 2 to 3

Write a half equation for oxiygen reduction to hydroxide.

Balance electrons and combine half equations.

The ligands on the cobalt do not change.
Reply 4
Avatar for HG1
HG1
OP
Original post by TeachChemistry
You've missed the cobalt off but no matter.

Write a half equation for cobalt oxidation from 2 to 3

Write a half equation for oxiygen reduction to hydroxide.

Balance electrons and combine half equations.

The ligands on the cobalt do not change.



thanks alot ! really helped
Reply 5
Avatar for HG1
HG1
OP
Original post by TeachChemistry
You've missed the cobalt off but no matter.

Write a half equation for cobalt oxidation from 2 to 3

Write a half equation for oxiygen reduction to hydroxide.

Balance electrons and combine half equations.

The ligands on the cobalt do not change.


This is how far I get , not sure where I went wrong ? And how do you know that oxygen is reduced to hydroxide ?
Original post by HG1
This is how far I get , not sure where I went wrong ? And how do you know that oxygen is reduced to hydroxide ?


Your first equation is correct.

The second is not correct. You can't have H+ and OH- in the same equation like that.

Try this:

2H2O + O2 + 4e- --> 4OH-

now you finish off

Quick Reply

Latest