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second order differencec eqn

in theory do i actually need the constant A to be given or could i work it out by simultaneous methods?

https://cdn.discordapp.com/attachments/322819040059850757/371334434110177280/unknown.png

Reply 1

DFranklin

Original post by will'o'wisp2

in theory do i actually need the constant A to be given or could i work it out by simultaneous methods?

https://cdn.discordapp.com/attachments/322819040059850757/371334434110177280/unknown.png

I see no constant A in your attachment. Regardless of that, knowing p0 and p1 is enough to completely determine the solution.

Reply 2

will'o'wisp2

Original post by DFranklin

I see no constant A in your attachment. Regardless of that, knowing p0 and p1 is enough to completely determine the solution.

Sorry i was going off my notes. the constant i deem "A" is 307 and i just worked it out. Horrible bit of work if you don't sub and try and work each bit out. :P It's 307.3.... so ye noice

Thanks man

Reply 3

DFranklin

Original post by will'o'wisp2

Sorry i was going off my notes. the constant i deem "A" is 307 and i just worked it out. Horrible bit of work if you don't sub and try and work each bit out. :P It's 307.3.... so ye noiceJust a matter of "practicality", it's almost certainly easiest here to simply apply the recurrence twice to find P2 and then P3. It's something a GCSE student could do, but it's also the least calculation.

Edit: and to be clear, in that case you never need to work out the "correct" value for A.

Reply 4

will'o'wisp2

Original post by DFranklin

Just a matter of "practicality", it's almost certainly easiest here to simply apply the recurrence twice to find P2 and then P3. It's something a GCSE student could do, but it's also the least calculation.

Edit: and to be clear, in that case you never need to work out the "correct" value for A.