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Chem help rates

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Original post by Roxibox123
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From experiment 17 to 18
W concentration increased by 2.5, X concentration remained constant, rate increased by 6.25. 2.5 raised to the second power is 6.25. So W is second order.
From experiment 18 to 19
W concentrated increased by 2, it is second order, so rate increase by 4. X concentration increased by 2. Rate increased by 4.
4 x X = 4
X = 1
2^0 = 1
So X is zero order
rate = k[W]2
Substitute an experiment to find k.
Units are (mol dm3 s-1)/(mol dm3)2 = (mol dm3)-1 s-1 = mol-1dm-3s-1

To answer this question, look between 2 experiments and find one with one of the reactants being constant. You can than find the order of the reactant.
If all equations have changing concentrations between them all, you will have to use algebra (unlikely)
(edited 6 months ago)

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