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Distance travelled from displacement equation

How can I find the distance travelled given the equation for displacement and velocity between the values t=0 and t=6.62

t>=0
v = 8t-2/3t^3
s = t^2-1/3t^3+8t

I tried subbing 6.62 into the displacement equation and I got 0 (which is not the correct answer). Both 0 and 6.62 are roots of the displacement equation.

UPDATE: Integrating the velocity equation between 0 and 6.62 results in -144.80 (which is not the right answer; +144.8 is not as well)

(edited 6 years ago)

BUMP

What is the full text of the original question?

Reply 3

Adh231

Original post by old_engineer

What is the full text of the original question?

This is the full question.

(edited 6 years ago)

Reply 4

old_engineer

Original post by Kartheyan

This is the full question.

Well something doesn't add up as your expressions for displacement and velocity don't correspond to one another via differentiation / integration.

Reply 5

number0

It's probably because he stops then starts going in the opposite direction. Maybe try finding the times at which he has 0 velocity, at that time he is just about to turn and drive the other way. Then break the whole journey into smaller sections.

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Distance travelled from displacement equation

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