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Quadratic Inequalities GCSE MATHS

+ 6x + 8 < 0 pls help the online methods are so hard

tysm ppl :smile:
first step would be to factorise..
(edited 3 years ago)
Original post by Donnialy
+ 6x + 8 < 0 pls help the online methods are so hard

tysm ppl :smile:

How far have you got?

A good start would be to consider + 6x + 8 = 0
Reply 3
Hey guys so i tried to factorise and got

(x+2)(x+4) <0
x <-2, x < -4

How would I plot this on a graph or inequality line?

EG of equality line

_____________________
1 2 3 4 5 6 7 8 9 10

Sorry if this doesn't make sense
Original post by Donnialy
Hey guys so i tried to factorise and got

(x+2)(x+4) <0
x <-2, x < -4

How would I plot this on a graph or inequality line?

EG of equality line

_____________________
1 2 3 4 5 6 7 8 9 10

Sorry if this doesn't make sense

That's not the way I'd tackle it.
consider + 6x + 8 = 0
(x + 2)( x + 4) = 0

x = -2 or -4

Sketch the curv and we want the x values which give the curve below the x-axis -4 < x < -2 not sure where you got your inequalities ...

Do you know how to show this on the number line?
Original post by Donnialy
Hey guys so i tried to factorise and got

(x+2)(x+4) <0
x <-2, x < -4

How would I plot this on a graph or inequality line?

EG of equality line

_____________________
1 2 3 4 5 6 7 8 9 10

Sorry if this doesn't make sense

You've made an error here (but not in the factorising). Try drawing a graph of the equation (ie draw y = x^2 + 6x + 8) - you're looking for any areas where y < 0 (since the quadratic is less than 0).

For the question about the numberline:


Hopefully the above image might help you a bit. But try the graph trick first and see where that lands you.
Reply 6
Original post by Muttley79
That's not the way I'd tackle it.
consider + 6x + 8 = 0
(x + 2)( x + 4) = 0

x = -2 or -4

Sketch the curv and we want the x values which give the curve below the x-axis -4 < x < -2 not sure where you got your inequalities ...

Do you know how to show this on the number line?


wait so all i have to do is draw the graph and look for a number for x which is between -2 and -3 ?!? ahh I can do that! tysm for helping :smile:
Reply 7
Original post by themagicturtle
You've made an error here (but not in the factorising). Try drawing a graph of the equation (ie draw y = x^2 + 6x + 8) - you're looking for any areas where y < 0 (since the quadratic is less than 0).

For the question about the numberline:


Hopefully the above image might help you a bit. But try the graph trick first and see where that lands you.

tysm for replying, i think that image will rlly help :smile: someone else said about the graph too, imma try that.
Original post by Donnialy
tysm for replying, i think that image will rlly help :smile: someone else said about the graph too, imma try that.

You need the graph to find the inequalities then use the number line with open circles on the -4 and -2 and a line joining them.
Reply 9
Original post by Muttley79
You need the graph to find the inequalities then use the number line with open circles on the -4 and -2 and a line joining them.

:smile: i think i got it ! tysm everyone for helping

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