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# D2 6th June 2013 watch

1. (Original post by Hamburglar)
Could you please screenshot the mark scheme or something? I can't really identify what you mean by zero.

If you're referring to the stages then, I don't think it matters what you call them really. You could arbitrarily call them 0-4 as you could 1-5 I believe. I also think they allow you to do the stages in whichever order (5-1 or 1-5).
It's the D2 mock paper try the dynamic programming questions in march they don't put a zero in storage or is it just me?
Smith
2. (Original post by smith50)
It's the D2 mock paper try the dynamic programming questions in march they don't put a zero in storage or is it just me?
Smith
Still not sure what paper you're referring to, sorry. :s I checked the specimen paper, and it doesn't look like it is that one.
3. Quick question if anyone can answer: is a lot of emphasis placed on stage numbering?

What I want to know is whether you are actually meant to give stage numbers forwards (1 to 4) or backwards (4 to 1).

Also, sometimes they have a stage 0 on mark schemes? What gives?

Thanks.
4. (Original post by smith50)
It's the D2 mock paper try the dynamic programming questions in march they don't put a zero in storage or is it just me?
Smith
If you look at February, there are no 0s in the destination column therefore you do not need to work out the 0 state for March as it will definitely not be used in your answer. Hope that helps

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5. (Original post by mathswiz:))
If you look at February, there are no 0s in the destination column therefore you do not need to work out the 0 state for March as it will definitely not be used in your answer. Hope that helps

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Hi have you tried the flows question in this paper i get 86 instead of 85 did you get the same?
Smith
6. (Original post by smith50)
Hi have you tried the flows question in this paper i get 86 instead of 85 did you get the same?
Smith
I got 85, which routes have you used?

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7. (Original post by mathswiz:))
i got 85, which routes have you used?

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saceht-9
sabeht-2
sbeht-4
sbecdht-12
sbecfht-7
8. (Original post by smith50)
saceht-9
sabeht-2
sbeht-4
sbecdht-12
sbecfht-7
Just gone through that and I can't see where you are getting the route sbecd(f?)ht -12 from. I get 7 for that route

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9. (Original post by mathswiz:))
Just gone through that and I can't see where you are getting the route sbecd(f?)ht -12 from. I get 7 for that route

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Could you post your working i really don't get it?
Thanks,
Smith
10. (Original post by smith50)
Could you post your working i really don't get it?
Thanks,
Smith
Hopefully its attached, I havn't tried sending things before This question is page 10. hope it helps
Attached Images
11. D2 Mock Paper AB (2).pdf (679.7 KB, 75 views)
12. (Original post by mathswiz:))
Hopefully its attached, I havn't tried sending things before This question is page 10. hope it helps
legend did you do the dynamic programming question to could you post that aswell please
You've been a great help
Thanks,
Smith
13. (Original post by smith50)
legend did you do the dynamic programming question to could you post that aswell please
You've been a great help
Thanks,
Smith
Glad i could help I have done the dynamic programming question but the file is too big
14. How do you work out the value of the game?
15. (Original post by knowledgecorruptz)
How do you work out the value of the game?

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16. (Original post by mathswiz:))

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Ah sorry, I meant for three equations?
17. (Original post by knowledgecorruptz)
Ah sorry, I meant for three equations?
What do you mean by 3 equations? You use the either of the two equations of the lines which intersect on your graph.

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18. (Original post by knowledgecorruptz)
Ah sorry, I meant for three equations?
If you mean 3 equations as in a linear programming problem, then you have to solve the linear programming problem using simplex tableaux.

Then, you can read off a value of P from the table, and you have to bear in mind that initially, you will probably have added numbers to each element so you have to subtract this.

At first you may have said, let v = value of the game to player A. Then add 5 to each element.

Therefore, V = v+5 (since you added 5 to make every element positive).

Since P=V, you read your value of P from the tableaux, subtract 5 and then you'll have the value of the game to A.
19. (Original post by mathswiz:))
What do you mean by 3 equations? You use the either of the two equations of the lines which intersect on your graph.

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I did that but it doesn't work.

Intersection is between 2p + 3 and 4 - p

So p = 1/3

So surely that value would be 3 and 2/3?

But the mark scheme says it should just be 3.

It's the specimen paper, btw.
20. (Original post by knowledgecorruptz)
I did that but it doesn't work.

Intersection is between 2p + 3 and 4 - p

So p = 1/3

So surely that value would be 3 and 2/3?

But the mark scheme says it should just be 3.

It's the specimen paper, btw.
Had a look and I'd say the mark scheme is wrong, theres quite a few mistakes on the mock and practise papers as well

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21. (Original post by mathswiz:))
Had a look and I'd say the mark scheme is wrong, theres quite a few mistakes on the mock and practise papers as well

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oh right, haha. Thank you

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Updated: June 11, 2013
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