You are Here: Home >< Maths

# OCR (not MEI) C2 - Wednesday 20th May 2015 watch

1. (Original post by eddy29)
May just be me, but 12.7 isn't in the range of 0 to 2pi
The range is meant to be 0 to 6pi. The graph stretched by sf 3 in the x direction.
2. (Original post by jamesplay73)
I got the perimeter as 22.7
Same. I think you're right
3. ARGGHHHHH...
Got all the questions right, apart from 9a) where I answered in degrees (I.e. 1080-a). There goes 3 marks any guesses at what 70/72 is UMS wise? I probably get 1 on the 2 marker for method.
4. (Original post by ella_chloe)
Anyone reckon 60 will be an a :/
lol, I would laugh
5. (Original post by MrPenguinPerson)
Same here I kept getting weird quadratics that didn't work, I have no idea what I was doing wrong... I have never seen a question like that in any c2 past papers before
For that question you set up the quadratic using the sum with 2N(continue sum formula) and then subtracting N-1 (and continuing sum formula) and hence you can set it up from there to get out 24 as the only viable solution
6. (Original post by Renzhi10122)
Same. I think you're right
I did too
7. (Original post by AlistairMcDonald)
I checked it manually, which was stupid, as I ran out of time by q9, but I got the same as he/she did
i got that answer at one point but cant remember if it was my final answer, i remember seeing i hadnt put brackets in on my calculator around the negative number and then i got a different answer surely if there is a negative number you put brackets around it? I might be wrong but just tryinh to see where i went wrong if i did!
8. Any guesses as to what the grade boundaries and ums boundaries would be?

Posted from TSR Mobile
9. (Original post by Jmedi)
For that question you set up the quadratic using the sum with 2N(continue sum formula) and then subtracting N-1 (and continuing sum formula) and hence you can set it up from there to get out 24 as the only viable solution
Yeah I did that several times and couldn't get a working quadratic. Must have made a silly arithmetic error. Hopefully get a few method marks
10. (Original post by xsanda)
Xsanda's solutions:
R=-2
ar¹⁰ = 3072
Sum to 20 = -1048575

trapezium: 21.4
narrower strips

triangle area: 32.1
perimeter: 20.7

expansion: 64+192ax+240a²x²+…
a=2/3

y=4x^(3/2)-7x-3
(x-2)(x+5)(x-3)
256
negative section of integration counts negatively

u₂₀ = 62
Σ = 517 (show that)

N=24
n=17.1
x=32, y=8

6π-α
3π-a
graph of sin, half height
3.32, 12.7
Charlie that you?
11. (Original post by Fletcher123)
Any guesses as to what the grade boundaries and ums boundaries would be?

Posted from TSR Mobile
My guess is 57 raw for an A
12. anyone know the answer to the 7 marker?
13. (Original post by AlistairMcDonald)
How did you all find it? I didn't think it was too difficult, but I ran out of time before I could even look at 9, and it looked like quite a nice question, too
You didn't do any of 9? It was 9 marks!
14. (Original post by rich1334)
Yeah I did that several times and couldn't get a working quadratic. Must have made a silly arithmetic error. Hopefully get a few method marks

Yeah the only maybe other thing missed if it wasn't a arithmetic error was that in that bracket was N-2 instead of N-1.

Question;
Did the first part of Q9 have to be in radians? (The one referring to alpha and has anyone been able to confirm if the answer to the last part is 3.32 and 12.7? Those were my solutions however I'm very unsure in 12.7 )
15. (Original post by Mr_hawaii)
lol, I would laugh
laugh at what sorry?
16. (Original post by xsanda)
Xsanda's solutions:
R=-2
ar¹⁰ = 3072
Sum to 20 = -1048575

trapezium: 21.4
narrower strips

triangle area: 32.1
perimeter: 20.7

expansion: 64+192ax+240a²x²+…
a=2/3

y=4x^(3/2)-7x-3
(x-2)(x+5)(x-3)
256
negative section of integration counts negatively

u₂₀ = 62
Σ = 517 (show that)

N=24
n=17.1
x=32, y=8

6π-α
3π-a
graph of sin, half height
3.32, 12.7
17. Can I just gauge how people felt that went, 1/10 being very badly, 10/10 being very well? Just so I get an idea of the standard. Reply to this post
18. (Original post by gabby07)
Can I just gauge how people felt that went, 1/10 being very badly, 10/10 being very well? Just so I get an idea of the standard. Reply to this post
fairly straightforward 10/10
19. (Original post by Nuvertion)
It was the sum of the first 20 terms, not the first 19 unfortunately
20. (Original post by Tobybeta)
ARGGHHHHH...
Got all the questions right, apart from 9a) where I answered in degrees (I.e. 1080-a). There goes 3 marks any guesses at what 70/72 is UMS wise? I probably get 1 on the 2 marker for method.
You may as well just resit the year now

### Related university courses

TSR Support Team

We have a brilliant team of more than 60 Support Team members looking after discussions on The Student Room, helping to make it a fun, safe and useful place to hang out.

This forum is supported by:
Updated: August 19, 2015
Today on TSR

### A-Level OCR Biology Unofficial Markscheme

Find out how you've done here

### 3,546

students online now

Exam discussions

### Find your exam discussion here

Poll
Useful resources

Can you help? Study help unanswered threadsStudy Help rules and posting guidelinesLaTex guide for writing equations on TSR

## Groups associated with this forum:

View associated groups

The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE