The Student Room Group
Reply 1
To do d/dx[xy] you have to use product rule. You get:

(1)(y) + (dy/dx)(x) = y + x(dy/dx)

(differentiate the first term, times by the other etc...)
Reply 2
think of it as a product of two functions and differentiate is as such.

d(xy)/dx = x(dy/dx) + y
Reply 3
Thanks a lot :-) I did know that, I just have my p5 paper tomorrow and I've had 4 modules of exams already this week and I'm too tired to think, but I need to revise! Sorry for asking a silly question!
Reply 4
are you on AQA too?
Reply 5
+ xy = 4x - 2

3y² dy/dx + (y + xdy/dx) = 4
3y² dy/dx + xdy/dx = 4-y
dy/dx(3y²+x) = 4-y
dy/dx = (4-y)/(3y²+x)
Reply 6
Yes i am

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