The Student Room Group
Reply 1
Yes

Consider each statement separately.
Reply 2
Is it wrong to say x^2 = a^2 ==> x = a? The only time P ==> Q fails is when P is true but Q is false. But Q here is x = a, which can be true even though it's not necessarily true. Do we need Q to be neccesarily true in order to write the implication sign? Surely if P was false, Q being false wouldn't matter - how is that taken into account when writing implications in general in mathematics?

Also, why doesn't (x = a or x = - a) ==> 2x^2 = 2a^2?
Reply 3
Swayum
Is it wrong to say x^2 = a^2 ==> x = a?
Yes.

Swayum
The only time P ==> Q fails is when P is true but Q is false. But Q here is x = a, which can be true even though it's not necessarily true. Do we need Q to be neccesarily true in order to write the implication sign? Surely if P was false, Q being false wouldn't matter - how is that taken into account when writing implications in general in mathematics?
We don't need Q to be necessarily true. I think the misunderstanding lies in the fact that your definition of => is slightly incomplete. You should say that "P -> Q" just in case in all the possible worlds in which P is true, Q is also true. In other words, P->Q doesn't hold if there exists a POSSIBLE WORLD in which P is true and Q is false. (And in the case under consideration, there does exist such a world. The world where x = -2 and a = 2 makes P true, but Q false.)

This "possible worlds" view should hopefully make things clearer to you. It is how you treat cases where the truth valuation of P and Q depends on the world you are looking at.

Also, why doesn't (x = a or x = - a) ==> 2x^2 = 2a^2?
It does.
Reply 4
Swayum
Is it wrong to say x^2 = a^2 ==> x = a? The only time P ==> Q fails is when P is true but Q is false. But Q here is x = a, which can be true even though it's not necessarily true. Do we need Q to be neccesarily true in order to write the implication sign? Surely if P was false, Q being false wouldn't matter - how is that taken into account when writing implications in general in mathematics?

Also, why doesn't (x = a or x = - a) ==> 2x^2 = 2a^2?


I think an easier way to think about it is just to read it in english. x^2 = a^2 ==> x = a reads "x^2 = a^2 implies x = a".

But clearly that's not the case, because you could have x = 1, a = -1, and then you'd have x^2 = a^2 but not x = a. So it can't be the case that x^2 = a^2 implies x = a.
Reply 5
last step is wrong:
this implies(both way) x=a or x=-a , but x can't be equal to -a ( from 1)
this implies x=a.
Reply 6
carreshwell
last step is wrong:
this implies(both way) x=a or x=-a , but x can't be equal to -a ( from 1)
this implies x=a.


No it's not

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