Year 12s: what will be the first way you research your future options? >>

Year 12s: what will be the first way you research your future options? >>

Year 12s: what will be the first way you research your future options? >>

A little Integration help plz.

Integrate with respect to x.

1. tan2x

This is like the first exercise in the bloody FP2 book, I've done like all C3 Diffentiation and C4 Integration to get to this stage and I'm stuck already on one of the first few questions oh dear.

Ok what I've done so far I've tried changing it to sin2x/cos2x and meddling around with identities but have not gotten to a form I can integrate. I've also tried to use the tan2A identity and that hasnt simplified anything . Can someone get me started please.

what's the derivative of cos2x? dot dot dot

OP

Rocious

what's the derivative of cos2x? dot dot dot

You've got me thinking now, so my approach to make it sin2x/cos2x was right ye? and I now have to look and the general pattern where the rule is something like I = kf'(x) / f(x) ? right track?

yeah

OP

Rocious

yeah

Hmmm that don't seem to work man. :/ the answer at the back is 0.5sec2x which aint what I'm getting.

gman2k8

Hmmm that don't seem to work man. :/ the answer at the back is 0.5sec2x which aint what I'm getting.

You mean 0.5ln(sec2x)

gman2k8

Hmmm that don't seem to work man. :/ the answer at the back is 0.5sec2x which aint what I'm getting.

integral of tanx=ln|secx| +c
this is in your formula book
can you find tan2x from there?

OP

ukdragon37

You mean 0.5ln(sec2x)

Nope just rechecked the answer its 0.5sec2x.

gman2k8

Nope just rechecked the answer its 0.5sec2x.

thats wrong then..

it is definitely -0.5ln(cos2x) = 0.5ln(sec2x) .. differentiate to check if you want

gman2k8

Nope just rechecked the answer its 0.5sec2x.

Then it's a misprint. It's definitely 0.5ln|2x| + c

EDIT: Sorry, should be 0.5ln|sec(2x)| + c

Spoiler

OP

ukdragon37

Then it's a misprint. It's definitely 0.5ln|2x| + c

It was starting to freak me out seriously, I'm not so confident in my maths but I knew there had to be an ln somewhere there. Thanks :smile:

:smile:

ukdragon37

Then it's a misprint. It's definitely 0.5ln|2x| + c

!!!!
Not 0.5ln|sec(2x)| + c ?

meatball893

!!!!
Not 0.5ln|sec(2x)| + c ?

OOOPS

:o:

I typed it right the first time

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