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Hi can anyone give me some help on this question i'm not sure where to start

A particle, of mass 8kg, is attached to one end of a length of elastic string. The particle is placed on a smooth horizontal surface. The other end of the elastic string is attached to a point O fixed on the horizontal surface.

The elastic string had natural length 1.2m and modulus of elasticity 192N.

The particle is set in motion on the horizontal surface so that it moves in a circle, centre O, with a constant speed 3m/s.

Find the radius of the circle.


any help please?



i've ended up with a quadratic which i solved and selected the positive solution
my final answer for the radius is 1.5m can anyone confirm?
(edited 13 years ago)
Use F=mv2rF= \dfrac{mv^{2}}{r}
(edited 13 years ago)
Reply 2
Original post by jonathan3909
Use F=mv2rF= \dfrac{mv^{2}}{r}


is v revolutions per minute? how do i convert it?
also is F the centripetal force?
Original post by hey_its_nay
is v revolutions per minute? how do i convert it?
also is F the centripetal force?



F is the centripetal force (tension in the string) , v is the constant speed and m is the mass.
Reply 4
Original post by jonathan3909
F is the centripetal force (tension in the string) , v is the constant speed and m is the mass.

and the tension in the sting also equals ?x/l
?=192, l=1.2 but is x(the extention) r-l?
(edited 13 years ago)
Original post by hey_its_nay
and the tension isn the sting also equals ?x/l
?=192, l=1.2 but is x(the extention) r-l?


Modulus of elasticity has no use here.The centripetal forces is the tension = 80N.
Reply 6
Original post by jonathan3909
Modulus of elasticity has no use here.The centripetal forces is the tension = 80N.


can you show me how you found the tension please?
(edited 13 years ago)
Original post by hey_its_nay
and the tension in the sting also equals ?x/l
?=192, l=1.2 but is x(the extention) r-l?


Moreover in these types of questions , the length of the string is taken as the radius and since it is attached to a fixed point , the answer must be 1.2m!(think of it for yourself:rolleyes:)
Original post by hey_its_nay
can you show me how you the tension please?


Tension = mg
= (9.81 x 8)
= 78.48N ~ 79N
Reply 9
Original post by jonathan3909
Moreover in these types of questions , the length of the string is taken as the radius and since it is attached to a fixed point , the answer must be 1.2m!(think of it for yourself:rolleyes:)


but its an elastic string so as it starts spinning around in a circle its going to stretch
im confused
Reply 10
Original post by jonathan3909
Tension = mg
= (9.81 x 8)
= 78.48N ~ 79N

its a horizontal circle why are you using g
Reply 11
i've ended up with a quadratic which i solved and selected the positive solution
my final answer for the radius is 1.5m can anyone confirm?

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