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FP1 OCR(not MEI) Jan 2011

I haven't found another thread so here's one. How did people find it?

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I thought it was pretty good, finished with time to spare, so just hoping I made no silly mistakes
Reply 2
It was good i think :P no 3x3 inverse matrix which was nice :smile: I am unsure on the question when you had to state whether the simultaneous equations were none, unique or infinite. I put none because of some inconsistency with equations but some of my friends say they put infinite does anyone know which ones right?
I am unsure on the question when you had to state whether the simultaneous equations were none, unique or infinite. I put none because of some inconsistency with equations but some of my friends say they put infinite does anyone know which ones right?

I put infinite, but I was unsure about that too
Original post by mrppaulo
It was good i think :P no 3x3 inverse matrix which was nice :smile: I am unsure on the question when you had to state whether the simultaneous equations were none, unique or infinite. I put none because of some inconsistency with equations but some of my friends say they put infinite does anyone know which ones right?


Hmm yeah I was unsure of this too. I got inconsistent because if you did the first equation minus 3 times the last equation you got something equal to 0. You can make this equal to the middle equation they gave you as that was also equal to 0. Solving that showed one side was -2 times the other side... that means inconsistent, right?

The rest was easy as cake! or should I say Pi? :wink:
Reply 5
Here are my answers:

(not too sure about q6 and i've prob made some stupid mistakes)

1.i. (7 9)
ii. (18)
iii. ( 12 -4
6 -2)

2.i. -12 + 13i
ii. 27/37 -(14/37)i

3. Induction

4. a=4 b=-4

5. A^2

6.i. x=4 y=x-2
ii. i shaded the area between x=4 , y=x-2 and the x-axis

7.i. A= (1 3
0 1)

ii. Enlargement SF root 3

iii. a. the coordinates of my points were (0,0) (2,0) (6,2) (8,2)
b. det=4 area quadrupled

8.i. show p=5/6
ii. q=2/3

9.i. det = a^2 -7a +6
ii. a=1, a=6
iii. equations consistent, det=0, therefore infinite solutions

10.i. show = 2/(r(r+1)(r+2))
ii. sum= 0.5 + 1/(n+2) - 1/(n+1)
iii. prove sum infinity from n+1 = 1/(n+1)(n+2)
Reply 6
for Q6) I shaded an equilateral triangle co-ords (0, -2) (4,-2) and (4,2)
q
8ii) i got q=1/3

all others i got same
(edited 13 years ago)
Reply 7
Original post by ziigmund
for Q6) I shaded an equilateral triangle co-ords (0, -2) (4,-2) and (4,2)
q
8ii) i got q=1/3

all others i got same


i got these too
Original post by ziigmund
for Q6) I shaded an equilateral triangle co-ords (0, -2) (4,-2) and (4,2)
q
8ii) i got q=1/3

all others i got same


I got the same for 6
Not sure what i got for 8ii, but my friends said 1/3
Reply 9
your 7i) is incorrect, and your 6ii) i think you shade the area between y=-2(rather than the x axis), x=4 and y =x-2
your 8ii) is 1/3
Reply 10
Ah well, i'll only have lost a few marks, hopefully
Reply 11
MR M please show us the way :P
Reply 12
Original post by busbybabe
your 7i) is incorrect, and your 6ii) i think you shade the area between y=-2(rather than the x axis), x=4 and y =x-2
your 8ii) is 1/3


Im pretty sure 7i) is a matrix of (1 3
...................................................01)

because that moves (1,1) to (4,1)
and (0,1) to (3,1) which is the correct transformation?
Original post by mattypb
Here are my answers:

(not too sure about q6 and i've prob made some stupid mistakes)

1.i. (7 9)
ii. (18)
iii. ( 12 -4
6 -2)

2.i. -12 + 13i
ii. 27/37 -(14/37)i

3. Induction

4. a=4 b=-4

5. A^2

6.i. x=4 y=x-2
ii. i shaded the area between x=4 , y=x-2 and the x-axis

7.i. A= (1 3
0 1)

ii. Enlargement SF root 3

iii. a. the coordinates of my points were (0,0) (2,0) (6,2) (8,2)
b. det=4 area quadrupled

8.i. show p=5/6
ii. q=2/3

9.i. det = a^2 -7a +6
ii. a=1, a=6
iii. equations consistent, det=0, therefore infinite solutions

10.i. show = 2/(r(r+1)(r+2))
ii. sum= 0.5 + 1/(n+2) - 1/(n+1)
iii. prove sum infinity from n+1 = 1/(n+1)(n+2)

I think I disagree with quite a lot of those. We'll wait for Mr M's solutions.
Reply 14
Mattyps coordinates are defos correct. Draw the shape and work out the area using squares and triangles, you'll find you get 4 which is what it should be. Also for the sum question, I got a=4 and b=-1, anyone get that?
Original post by UFK
Mattyps coordinates are defos correct. Draw the shape and work out the area using squares and triangles, you'll find you get 4 which is what it should be. Also for the sum question, I got a=4 and b=-1, anyone get that?

a=4, b=-4 is what me and a lot of others who sat FP1 at my college got.
Original post by mrppaulo
Im pretty sure 7i) is a matrix of (1 3
...................................................01)

because that moves (1,1) to (4,1)
and (0,1) to (3,1) which is the correct transformation?


agreed.
Reply 17
Original post by Farhan.Hanif93
a=4, b=-4 is what me and a lot of others who sat FP1 at my college got.


I second this answer :wink:
Original post by Farhan.Hanif93
a=4, b=-4 is what me and a lot of others who sat FP1 at my college got.


i got that too. and checked it on my calculator.
(edited 13 years ago)
Original post by snowboardinsteve
i got that too. and checked it on my calculator.

The only thing I actually checked on my Calculator was Q1ii and iii because I hadn't come across matrix multiplication like that before (only started revising last night so only got 2 papers in as a warm up :wink:)

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