# Further Maths Summations Help

Hello,
Could someone please explain why you would do the answer to (ii) subtracted from (iii)a to get the answer for (iii)b?

I do not understand how this works. I've also attached what I thought the answer would be. For reference, this is question 9 from Jan 2006 FP1 OCR paper.
(edited 10 months ago)
Just writing it out as a simple series you have
sum from n+1 to inf = sum from 1 to inf - sum from 1 to n
or equivalently as per the previous comment
sum from 1 to n + sum from n+1 to inf = sum from 1 to inf

Its one way to derive the sum to n formula of a geometric series, based on the infinite sum. The numerator is a - ar^(n+1) which represents
sum from 1 to inf - sum from n+1 to inf
as ar^(n+1) is the first term in the geometric series that starts at n+1.
(edited 10 months ago)
Original post by mqb2766
Just writing it out as a simple series you have
sum from n+1 to inf = sum from 1 to inf - sum from 1 to n
or equivalently as per the previous comment
sum from 1 to n + sum from n+1 to inf = sum from 1 to inf

Its one way to derive the sum to n formula of a geometric series, based on the infinite sum. The numerator is a - ar^(n+1) which represents
sum from 1 to inf - sum from n+1 to inf
as ar^(n+1) is the first term in the geometric series that starts at n+1.

So sum from n+1 to inf = sum from 1 to inf - sum from 1 to n is always true for any summations?
Original post by action123
So sum from n+1 to inf = sum from 1 to inf - sum from 1 to n is always true for any summations?

You could have written down a simple example but f the series was the sum of natural numbers (ignoring the fact that the infinite sum doesnt converge...) then the sum from 1 to infinity is
1 + 2 + 3 +....+ n + (n+1) + (n+2) + ...
Obviously you can write this as
[1 + 2 + 3+....+n] + [(n+1) + (n+2) + ... ]
so
sum from 1 to n + sum from (n+1) to inf = sum from 1 to inf

You shouldnt have to remember it, it drops out of the definition of the series (splitting at n/n+1). Assuming the sum to infinity converges, then its true for any series.
(edited 10 months ago)