Edexcel GCSE Maths linear higher calculator

Is it possible that regions will come up in this exam?
Have they ever come up before?

I am crossing my fingers that this exam is much easier than Mondays :frown:

Reply 1

Baa

yes regions have come up and it is possible that it can come up. however, it is more likely to come up in non calculator, so one cannot be sure

Reply 2

.matrix

can someone please help me out with this question. i know the answer but i dont know how to work it out...

"prove that (3nplus1)^2 - (3n-1)^2 is a multiple of 4, for all the positive interger values of n."
-june 2009 paper
btw the answer is 12n

Reply 3

HumaIsBatman

Original post by .matrix

can someone please help me out with this question. i know the answer but i dont know how to work it out...

"prove that (3nplus1)^2 - (3n-1)^2 is a multiple of 4, for all the positive interger values of n."
-june 2009 paper
btw the answer is 12n

By working out the answer, which is 12n, isn't that proof itself?

Reply 4

.matrix

Original post by HumaIsBatman

By working out the answer, which is 12n, isn't that proof itself?

but how do you get there. i only know the answer bcause of the mark scheme.

Reply 5

Saif95

OP

12

Original post by .matrix

can someone please help me out with this question. i know the answer but i dont know how to work it out...

"prove that (3nplus1)^2 - (3n-1)^2 is a multiple of 4, for all the positive interger values of n."
-june 2009 paper
btw the answer is 12n

(3n+1)^2 = (3n+1)(3n+1) multiplying out gives you 9n^2+6n+2
(3n-1)^2 = (3n-1)(3n-1) multiplying out gives you 9n^2-6n+2

9n^2+6n+2 - 9n^2-6n+2 = 9n^2 take away 9n^2 gives you nothing. 6n--6n is 12n and 2-+2 = 0.

So you are left with 12n which is a multiple of 4.

This is one of the easier proof questions.

Reply 6

.matrix

Original post by Saif95

(3n+1)^2 = (3n+1)(3n+1) multiplying out gives you 9n^2+6n+2
(3n-1)^2 = (3n-1)(3n-1) multiplying out gives you 9n^2-6n+2

9n^2+6n+2 - 9n^2-6n+2 = 9n^2 take away 9n^2 gives you nothing. 6n--6n is 12n and 2-+2 = 0.

So you are left with 12n which is a multiple of 4.

This is one of the easier proof questions.

No hope for me then! Thanks for the explanation! :smile:

Reply 7

johnnyauwhiz

1

hey does anyone have the higher past papers and mark schemes for november 2005?

Reply 8

Baa

Original post by johnnyauwhiz

hey does anyone have the higher past papers and mark schemes for november 2005?

Here they are :smile:

November 2005 Paper 5.pdf478.7KB

November 2005 Paper 6.pdf414.3KB

November 2005 Mark Scheme.pdf671.6KB

Reply 9

johnnyauwhiz

1

Original post by Baa

Here they are :smile:

awesome thanks a lot! :smile:

Reply 10

username810220

what do you guys reckon the hardest thing will be on the calc paper? i don't know what to revise!!!!!! oh and i also hope it's a lot better than monday's, otherwise bye bye A* :frown:

Reply 11

itsmagic

10

Original post by Baa

Here they are :smile:

Thank you so much! I'm so worried about this exam!

Reply 12

rolawumi

does anyone know how to solve this equation?
7-(x+1) = 9-(2x-1)

I keep messing up the working out, I don't know how to multiply it out :s

the answer is meant to be "4" by the way

Reply 13

accesstohe

3

Original post by rolawumi

does anyone know how to solve this equation?
7-(x+1) = 9-(2x-1)

I keep messing up the working out, I don't know how to multiply it out :s

the answer is meant to be "4" by the way

Why is there a minus sign in front of the brackets?! I've never seen this before or in any of the past papers

Reply 14

bananarama2

Original post by rolawumi

does anyone know how to solve this equation?
7-(x+1) = 9-(2x-1)

I keep messing up the working out, I don't know how to multiply it out :s

the answer is meant to be "4" by the way