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AQA Mathematics Module 5 Paper 2H (Calc) Unofficial Answers (10/06/2011)

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Reply 40
Original post by cathyds
what about the very last question????


Can you remember the details?


Areas were equal, but what were the side lengths?

I think one of rectangles was 2x, but I don't remember any others.
Reply 41
Very last question:
Square of length 3y-2x and rectangle of lengths 3y+2x and 2x have equal area. Prove y is a multiple of x.
(3y-2x)(3y-2x)=2x(3y+2x)
9y2-12xy+4x2=6xy+4x2
9y2=18xy
9y=18x
Therefore y=2x
(edited 12 years ago)
Reply 42
To re-arrange trapezium formula:

A = 1/2(a+b)h
== A/h = 1/2(a+b)
== (-1/2)b = (1/2)a - A/h
== -b = a - (2A)/h
== b = -a + (2A)/h
Original post by FO12DY
Can you remember the details?


Areas were equal, but what were the side lengths?

I think one of rectangles was 2x, but I don't remember any others.


I wrote that one on some tracing paper.

The areas of the square and the rectangle are equal. Show that y is a multiple of x

Square side length - (3y-2x)
Rectangle long side length - (3y+2x)
Rectangle short length - 2x
(edited 12 years ago)
Reply 44
Original post by RedUnited
Very last question:
Square of length 3y-2x and rectangle of lengths 3y+2x and 2x have equal area. Prove y is a multiple of x.
(3y-2x)squared=2x(3y+2x)
9y2-12xy+4x2=6xy+4x2
9y2=18xy
9y=18x
Therefore y=2x



Ah, thanks Red, was missing those details :wink:


Linked from first post.
Reply 45
y=2x
I got lucky, i randomly subbed in y=4 and x=2 and it worked for me. I simplified the formula, subbed these in and they were equal to zero. I believe when you simplified it worked out to be 9y(y-18x)=0. If you sub the two values in you get 0 = 0.
Reply 46
Original post by FO12DY
Ah, thanks Red, was missing those details :wink:


Linked from first post.


No probs, trying to think of any other questions I can remember
Reply 47
Hmm, well we have 14 questions, but there were at least 16 - we have the 15th, and the last one.

Can't remember any others though :/
Reply 48
Have we got the graph and inequality one up? y=3x-1, and then shade the region that satisfies the inequality y<3x-1
Reply 49
the cosine values has to be between 180n and 360 degrees :smile:
Reply 50
(1/3)x - 4 = 1/2
for this one i got -10.5 i think :s
Reply 51
15c you had to use the quadratic equation didn't you?
which got you 11 and 14.9...
Reply 52
anychance we can actually put all qs and answers in one bloody post! :P
Reply 53
i think there were 19 questions overall... could be wrong but i remember seeing that question number :P
Reply 54
should pi(a+b) be a length? because they're multiplying each other?
Reply 55
Original post by Wisdom
(1/3)x - 4 = 1/2
for this one i got -10.5 i think :s


I got that aswell :smile:
Reply 56
Original post by Wisdom
15c you had to use the quadratic equation didn't you?
which got you 11 and 14.9...


Wasn't it -1 and 4.25? It was given in the question that one of the solutions was -1 or am I talking about the wrong question
Reply 57
Can anyone remember the marks for the questions?
Reply 58
Original post by RedUnited
Have we got the graph and inequality one up? y=3x-1, and then shade the region that satisfies the inequality y<3x-1


Going up now.

Original post by Wisdom
the cosine values has to be between 180n and 360 degrees :smile:


Thanks, editing. I got that wrong in the exam, I put 120! *doh*

Original post by Wisdom
(1/3)x - 4 = 1/2
for this one i got -10.5 i think :s


Nope, x/3 = 9/2 so x = 27/2 and 27/2 is 13.5

Original post by Wisdom
15c you had to use the quadratic equation didn't you?
which got you 11 and 14.9...


Just checked it on my calculator (built in equation functions), definitely 4.25; -1

Original post by west28
anychance we can actually put all qs and answers in one bloody post! :P


That's what this threads for mate, check my first post, it's where I'm editing back in all the questions and answers :wink:

Original post by blahblahh
should pi(a+b) be a length? because they're multiplying each other?


I originally (and in the exam) wrote area. I have been (rightly) corrected though, even though pi is multiplying both a and b, they are then added together, so it is a sum of two lengths not a multiplication.

Original post by RedUnited
Wasn't it -1 and 4.25? It was given in the question that one of the solutions was -1 or am I talking about the wrong question


Nope, you're right on the money. x1= 4.25; x2 = -1.
Reply 59
Anyone remember any marks to go with each question??

Also I remembered another question - the one where u had to find the value of c, I think it was 0.8.

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