1. 544 (question about percentages 640x0.85)
2a)1/4 (probability question with coins)
b)50
3) apples =575 rasberries=500 (mixture for crumble)
4)54 (cant remember what the answer for this question was - thin it was the s=d/t one)
5i)a^4
ii)30ab
iii)q^6
b)-3.5 (equation)
c)24 (equation)
7)10 (the mean question when you had to find the number)
8) bisector question which you have to draw
9a)136.5 (lower bound
b)137.5 (upper bound)
10)3^2x2x7 (prime factors of126)
11)6.22 (think this was a trig or pyhtag)
12i)x>-3.5 (inequality)
ii)-3,-2,-1 (what negative integars suit it)
13a)earth (has larget diameter)
b)6790000 (writing the standard form as normal number)
c)7.22x10^6 (difference between 2 planets)
14)63 (trapezium question)
15a)2(x-3) --> (simplifying question)
b)(a+12)(a-12)
16) - historgram box = 300, 240
-diagram = 10sqs up, 2sqs up, 4sqs up
17)15/64 (probability question for being at least late once or something)
18) (the prve the reocurring decimal :smile:

x=0.396396396
1000x=396.396396396
1000x-x = 999
396.396396 - 0.396396 =396
396/999 divide by 3
132/333 divide by 3
44/111
19) 6.66 (the sinrule)
20a) 0 (excluded from domain)
b) 4 (composite)
c) 1/x-1 (iverse)
21a) explained above (shares question)
b)11.8 (finding the quadratic)
22a) 9.11 (cuboid question)
b)19.2
23)5root2 (surds)
24a)4b (vectors)
b) cant remember
c)cant remember
d) k = 4

(edited 12 years ago)

Reply 45

maramore

OP

1

Original post by the-chosen-one

What did you get for the area of the trapezium? How did you do it? I got really stuck :s-smilie:

Can't remember the actual value now, but I broke it down into a square and a right angled triangle. The area of the right angle triangle was 1/2 base x height, which was 1/2x2x5 I seem to recall, and you just added it to the area of the square.

Reply 46

ohtasha

Original post by maramore

It was 63.

The length ratio was 1:3 - so you had to cube it to get the area ratio, which was 1:9. Looks like you forgot to do that :frown:

Since the smaller one had an area of 7, the larger one would be 7x9=63 cm squared.

Yes, I realised that when I got out. It's not important though, it was only worth a couple of marks, and you get a mark for working.

Reply 47

ohtasha

Original post by maramore

Can't remember the actual value now, but I broke it down into a square and a right angled triangle. The area of the right angle triangle was 1/2 base x height, which was 1/2x2x5 I seem to recall, and you just added it to the area of the square.

Shouldn't the area have been 1/2absinC?
I've never ended up with the correct answer by doing 1/2 base x height.

Reply 48

mel95iac

4

am i the only person that did this for the shares question?!

(100+x)/100 = (600-5x)/50x
50x(100+x)=100(600-5x)
5000x+50x^2=60000-500x
50x^2+4500x-60000=0
x^2+90x-1200=0

Reply 49

mel95iac

4

Original post by ohtasha

Shouldn't the area have been 1/2absinC?
I've never ended up with the correct answer by doing 1/2 base x height.

it was a right-angle triangle so u didnt need the formula :s i think the answer is 35cm^2 if i understood the question u r talking abt

Reply 50

ohtasha

Original post by mel95iac

am i the only person that did this for the shares question?!

(100+x)/100 = (600-5x)/50x
50x(100+x)=100(600-5x)
5000x+50x^2=60000-500x
50x^2+4500x-60000=0
x^2+90x-1200=0

I couldn't do that question, and some of the people I asked at my school couldn't do it either, but someone else I asked showed me how to do it, although I can't remember their exact method.

Reply 51

maramore

OP

1

Original post by ohtasha

Shouldn't the area have been 1/2absinC?
I've never ended up with the correct answer by doing 1/2 base x height.

1/2absinC works for any triangle. Because Sin90=1, the formula for a right angled triangle can be simplified to 1/2 base x height (or 1/2ab). :smile:

Reply 52

ohtasha

Original post by mel95iac

it was a right-angle triangle so u didnt need the formula :s i think the answer is 35cm^2 if i understood the question u r talking abt

Oh I got that answer with the formula.

Reply 53

master y

12

Original post by ohtasha

I think I had -4.

I changed it to 1/4!!! Apparently its just 4 though . I got all the working out right though. :rolleyes:

This paper was extremely ewasy. What did you get for the gf(a) = 3??? i got 2.5...

Reply 54

the-chosen-one

2

Original post by maramore

Can't remember the actual value now, but I broke it down into a square and a right angled triangle. The area of the right angle triangle was 1/2 base x height, which was 1/2x2x5 I seem to recall, and you just added it to the area of the square.