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Core 1,Linear graph question

The line Ab has equaiton 3x+5y=8 and the point a has coordiantes (6,-2)

a). the point c has coordinates (2,k) and the distance from a to c is 5, Find the two possible values of constant k
Reply 1
Well you know the distance formula right? Plug the values you know in

E.g. AC= 5

Which means-> (6-2)^2+ (-2-k)^2= 25

Ill leave you to do the rest.
Reply 2
Original post by f1mad
Well you know the distance formula right? Plug the values you know in

E.g. AC= 5

Which means-> (6-2)^2+ (-2-k)^2= 25

Ill leave you to do the rest.


Well i got 16+(k+2)^2=25, i expand the bracket right?
Reply 3
Original post by Gary
Well i got 16+(k+2)^2=25, i expand the bracket right?


No; leave it and subtract 16 from both sides.

Take the square root and you'll have 2 possible values.
Reply 4
Ahhh got it, thankj you :smile:

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