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    The line Ab has equaiton 3x+5y=8 and the point a has coordiantes (6,-2)

    a). the point c has coordinates (2,k) and the distance from a to c is 5, Find the two possible values of constant k
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    Well you know the distance formula right? Plug the values you know in

    E.g. AC= 5

    Which means-> (6-2)^2+ (-2-k)^2= 25

    Ill leave you to do the rest.
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    (Original post by f1mad)
    Well you know the distance formula right? Plug the values you know in

    E.g. AC= 5

    Which means-> (6-2)^2+ (-2-k)^2= 25

    Ill leave you to do the rest.
    Well i got 16+(k+2)^2=25, i expand the bracket right?
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    (Original post by Gary)
    Well i got 16+(k+2)^2=25, i expand the bracket right?
    No; leave it and subtract 16 from both sides.

    Take the square root and you'll have 2 possible values.
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    Ahhh got it, thankj you
 
 
 
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