# M1,Heinemann EX2D 9Watch

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#1
hi
a particle has a position vector 2i+j initially and is moving with speed 10ms in the direction 3i+4j.find its position vector when t=3.

0
#2
the answer at the back of the book sais it is 20i-23j?
0
13 years ago
#3
velocity = sqrt (3²+4²) = 5
Its moving direction 3i-4j at 10m/s . 10/5=2
velocity vector=2(3i-4j)=6i-8j

After 3 seconds position vector is
r=(2i+j)+3(6i-8j)
r=20i-3j
0
#4
(Original post by Malik)
velocity = sqrt (3²+4²) = 5
Its moving direction 3i-4j at 10m/s . 10/5=2
velocity vector=2(3i-4j)=6i-8j

After 3 seconds position vector is
r=(2i+j)+3(6i-8j)
r=20i-3j
whats 10/5 for?
0
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