tndfr
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#1
Report Thread starter 13 years ago
#1
hi
a particle has a position vector 2i+j initially and is moving with speed 10ms in the direction 3i+4j.find its position vector when t=3.

it is driving me up the wall ,please help
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tndfr
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#2
Report Thread starter 13 years ago
#2
thanks for the reply,
the answer at the back of the book sais it is 20i-23j?
how did they come up with this number, please help
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Malik
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#3
Report 13 years ago
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velocity = sqrt (3²+4²) = 5
Its moving direction 3i-4j at 10m/s . 10/5=2
velocity vector=2(3i-4j)=6i-8j

After 3 seconds position vector is
r=(2i+j)+3(6i-8j)
r=20i-3j
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tndfr
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#4
Report Thread starter 13 years ago
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(Original post by Malik)
velocity = sqrt (3²+4²) = 5
Its moving direction 3i-4j at 10m/s . 10/5=2
velocity vector=2(3i-4j)=6i-8j

After 3 seconds position vector is
r=(2i+j)+3(6i-8j)
r=20i-3j
whats 10/5 for?
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