Quite simple problem,
can someone explain to me how 2/(2x+1) integrated ends up to be ln l2x+1l ?
I just need to see the proof of why the 2 infront of the x cancels with the 2 from the top, i.e 2/2 ln l2x+1l equals ln l2x+1l
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- Thread Starter
- 14-06-2006 16:25
- 14-06-2006 16:29
You always divide by the differential, so you end up with 2ln|2x+1|/2
Then the 2's cancel leaving you with ln|2x+1|
- 14-06-2006 16:30
proof = differentiate it back
- 14-06-2006 16:31
well when you Integrate you have to divide the result by the differential of what you are taking the log of. ie 2/2 ln (2x+1)
or you can say when the numerator is the differential of the denominator, the integral is the ln of the denominator.