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Another C4 Integration Problem........
Quite simple problem,
can someone explain to me how 2/(2x+1) integrated ends up to be ln l2x+1l ?
I just need to see the proof of why the 2 infront of the x cancels with the 2 from the top, i.e 2/2 ln l2x+1l equals ln l2x+1l
can someone explain to me how 2/(2x+1) integrated ends up to be ln l2x+1l ?
I just need to see the proof of why the 2 infront of the x cancels with the 2 from the top, i.e 2/2 ln l2x+1l equals ln l2x+1l
You always divide by the differential, so you end up with 2ln|2x+1|/2
Then the 2's cancel leaving you with ln|2x+1|
Then the 2's cancel leaving you with ln|2x+1|
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