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# Another C4 Integration Problem........ watch

1. Quite simple problem,

can someone explain to me how 2/(2x+1) integrated ends up to be ln l2x+1l ?

I just need to see the proof of why the 2 infront of the x cancels with the 2 from the top, i.e 2/2 ln l2x+1l equals ln l2x+1l
2. You always divide by the differential, so you end up with 2ln|2x+1|/2
Then the 2's cancel leaving you with ln|2x+1|
3. proof = differentiate it back
4. well when you Integrate you have to divide the result by the differential of what you are taking the log of. ie 2/2 ln (2x+1)

or you can say when the numerator is the differential of the denominator, the integral is the ln of the denominator.

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Updated: June 14, 2006
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