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    Quite simple problem,

    can someone explain to me how 2/(2x+1) integrated ends up to be ln l2x+1l ?

    I just need to see the proof of why the 2 infront of the x cancels with the 2 from the top, i.e 2/2 ln l2x+1l equals ln l2x+1l
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    You always divide by the differential, so you end up with 2ln|2x+1|/2
    Then the 2's cancel leaving you with ln|2x+1|
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    proof = differentiate it back
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    well when you Integrate you have to divide the result by the differential of what you are taking the log of. ie 2/2 ln (2x+1)

    or you can say when the numerator is the differential of the denominator, the integral is the ln of the denominator.
 
 
 
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Updated: June 14, 2006

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