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How do you integrate (1/x) dy/dx?

So am stuck on integrating this which is probably more simple than I think it is: (1/x) dy/dx


Note: this isn't just integrating (1/x) its integrating (1/x) with dy/dx!!

Thank You in advance
Reply 1
Original post by ihatebrownbread
So am stuck on integrating this which is probably more simple than I think it is: (1/x) dy/dx


Note: this isn't just integrating (1/x) its integrating (1/x) with dy/dx!!

Thank You in advance


This really needs to be asked in the Maths Forum (rather than Mathematics, which is the forum for questions about Uni courses rather than actual maths questions!), but I think the short answer is there is no simple formula for this.

What is the actual question that you've been asked?
Reply 2
Is it not just ln(x)+c?
Reply 3
Original post by lamp-y
Is it not just ln(x)+c?


That gives you 1/x when differentiated, not (1/x)(dy/dx)

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