Further maths integration question
Im trying to answer the following question:
Given that tan y = x arctan x , find dy/dx
Checking against the mark scheme, I've got down to the second to last step where the answer contains sec^2 y, but am unsure how to get that to become 1 + x^2 (arctan x)^2
Mark scheme: https://www.activeteachonline.com/default/player/document/id/786809/external/0/uid/357726
Given that tan y = x arctan x , find dy/dx
Checking against the mark scheme, I've got down to the second to last step where the answer contains sec^2 y, but am unsure how to get that to become 1 + x^2 (arctan x)^2
Mark scheme: https://www.activeteachonline.com/default/player/document/id/786809/external/0/uid/357726
Original post by Amy.fallowfield
Im trying to answer the following question:
Given that tan y = x arctan x , find dy/dx
Checking against the mark scheme, I've got down to the second to last step where the answer contains sec^2 y, but am unsure how to get that to become 1 + x^2 (arctan x)^2
Mark scheme: https://www.activeteachonline.com/default/player/document/id/786809/external/0/uid/357726
Given that tan y = x arctan x , find dy/dx
Checking against the mark scheme, I've got down to the second to last step where the answer contains sec^2 y, but am unsure how to get that to become 1 + x^2 (arctan x)^2
Mark scheme: https://www.activeteachonline.com/default/player/document/id/786809/external/0/uid/357726
blame pythagoras (identity) so
sec^2(y) = 1 + tan^2(y) = 1 + x^2
I cant see any need to introduce the cos^2 part near the end or the sqrt(), they seem to complicate things.
(edited 6 months ago)
Thank you!
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