maths word problem
150 slots in a race
7 teams competing
after trials each team has placed no more than 30 of its members on the race
no two teams have put the same number of cyclists on the race
what is the SMALLEST number of cyclists that the FOURTH largest team can have?
a 14
b 15
c 16
d 17
e 18
what i've worked out sofar:
150-30=120 (30 because one team has 30 at the most)
120/6 (because 6 teams are left out of the 7 - one took out 30 members)
120/6=20 for each
but they can't all be the same
what next?
7 teams competing
after trials each team has placed no more than 30 of its members on the race
no two teams have put the same number of cyclists on the race
what is the SMALLEST number of cyclists that the FOURTH largest team can have?
a 14
b 15
c 16
d 17
e 18
what i've worked out sofar:
150-30=120 (30 because one team has 30 at the most)
120/6 (because 6 teams are left out of the 7 - one took out 30 members)
120/6=20 for each
but they can't all be the same
what next?
Nevermind that, the answer is E) 18
Original post by 2smart4oxfart
150 slots in a race
7 teams competing
after trials each team has placed no more than 30 of its members on the race
no two teams have put the same number of cyclists on the race
what is the SMALLEST number of cyclists that the FOURTH largest team can have?
a 14
b 15
c 16
d 17
e 18
what i've worked out sofar:
150-30=120 (30 because one team has 30 at the most)
120/6 (because 6 teams are left out of the 7 - one took out 30 members)
120/6=20 for each
but they can't all be the same
what next?
7 teams competing
after trials each team has placed no more than 30 of its members on the race
no two teams have put the same number of cyclists on the race
what is the SMALLEST number of cyclists that the FOURTH largest team can have?
a 14
b 15
c 16
d 17
e 18
what i've worked out sofar:
150-30=120 (30 because one team has 30 at the most)
120/6 (because 6 teams are left out of the 7 - one took out 30 members)
120/6=20 for each
but they can't all be the same
what next?
Maximum number in first 3 teams is 30+29+28=87
Let x be number in 4th team.
Maximum number in bottom three teams=(x-1)+(x-2)+(x-3)=3x-6
87+x+3x-6= or < 150
Can you finish it from here?
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