I'm so confused about what happens when you dilute weak acids.
HA + H2O ->/<- H3O+ + A- I have in my notes (which I took from a mark scheme) that diluting a weak acid shifts the above equilibrium to the right and so the acid dissociates more, increasing the H+ concentration and therefore decreasing the pH.
But I just did a past paper (Edexcel CH04 January 2012) The bubble bath ‘Colour Change Matey’ has amongst its ingredients the weak acid benzoic acid, as well as the indicator bromocresol green. When it is added to bath water, its colour changes from yellow to blue.
Use the data booklet and value for pH of 0.0025moldm-3 of benzoic acid why the bubble bath changes colour when it is diluted by being added to the bath water.
For reference: pH of benzoic acid: 3.4 Bromocresol green: pKIn 4.7, yellow in acidic, blue in alkali. pH range is 3.8—5.4.
Mark scheme: - (pH) range (of indicator) 3.8 to 5.4 OR pKin= 4.7 - Bubble bath is (initially yellow since) pH less than 3.8 / is 3.4 -Adding of water/dilution (of acid) causes pH to rise/means [H+] decreases -Hence pH rises to ≥ 5.4 so blue/changes colour
So this question is saying that diluting it decreases [H+] and therefore increases the pH?
Diluting doesn't affect [H2O] by much - pure water is about 55 mol dm-3, adding a little weak acid won't change this much, so the equilibrium might shift slightly to the right, but not far.
Far more importantly, [H+] will decrease since you're diluting it, hence pH will rise.
Diluting doesn't affect [H2O] by much - pure water is about 55 mol dm-3, adding a little weak acid won't change this much, so the equilibrium might shift slightly to the right, but not far.
Far more importantly, [H+] will decrease since you're diluting it, hence pH will rise.