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AS chemistry past paper help

Can someone please explain to me how to get the answer 0.0524 from this question: ( it is January 2012 unit 1 AQA )

6 ) The metal lead reacts with warm dilute nitric acid to produce lead(II) nitrate,
nitrogen monoxide and water according to the following equation.

3Pb(s) + 8HNO3(aq) 3Pb(NO3)2(aq) + 2NO(g) + 4H2O(I)

6 (a) In an experiment, an 8.14 g sample of lead reacted completely with a 2.00 mol dm–3 solution of nitric acid.

Calculate the volume, in dm3, of nitric acid required for complete reaction.
Give your answer to 3 significant figures. (3 MARKS)

-thanks
Reply 1
Work out moles of Pb by 8.14/207 which will give you 0.0393.....Then divide it by 3 and multiply it by 8. Sub it into moles=conc x volume and you get 0.104 / 2 = 0.052431
Reply 2
oh I see now, thanks
Original post by Hood-Wink
Work out moles of Pb by 8.14/207 which will give you 0.0393.....Then divide it by 3 and multiply it by 8. Sub it into moles=conc x volume and you get 0.104 / 2 = 0.052431

Why do u divide by 3 and multiply by 8??
Original post by BRITISHDUCK
Why do u divide by 3 and multiply by 8??

Because the molar ratio of lead to nitric acid is 3:8 so you divide by 3 to get 1 mole of lead then times by 8 to get 8 moles of nitric acid.

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