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M1 Problem watch

1. A stone is thrown vertically upwards at a speed of 16m/s from a point h metres above the ground. the stone hits the ground 4secs later.

a) calculate the value of h

b)the speed of the stone as it hits the ground

2. am I stupid or do I need to know if it is thrown vertically upwards or downwards? anyway, you'll have to think about g when solving the problem.
3. oh yh vertically upwards sorry
4. For question 1

s=ut + (at^2)/2

(I think that formula will do...but there are other ones as well)

For question 2

V=u+at

v=velocity
u=initial velocity
a=acceleration
t=time
5. Take up as positive. The initial speed is 16m/s (u = 16), time is 4 seconds (t = 4), and the acceleration is 9.8m/s^2 down (a = -9.8). h is a distance. Do you know the formula connecting u, a, t, and distance (normally x or s)? For the second part - do you know a formula connecting u, a, t and the final speed (v), or can you read the above post and copy the formula?
6. hmm still nt sure
7. (Original post by EconomyMan)
hmm still nt sure
Oh, I see. You want me to do your work for you.

Not happening.
8. (Original post by generalebriety)
Oh, I see. You want me to do your work for you.

Not happening.
its not homework...im just doing it for revision...if i get a modell answer...i know what im working towards.
9. (Original post by EconomyMan)
its not homework...im just doing it for revision...if i get a modell answer...i know what im working towards.
You try it. I will guide you along the way if that's what you want. And when you've done that, I will provide you with a model answer and more examples if you're still not understanding. But I'd like you to try this, since it is revision and not learning.
10. I am not fond of solving whole problems either...

but I'll give you number 2...
(In White text)
v=u+at

a=-10m/s^2
t=4s
u=16m/s

hence v=-24m/s and as the question asks for speed and not velocity the answer is 24m/s
11. (Original post by nota bene)
I am not fond of solving whole problems either...

but I'll give you number 2...
(In White text)
v=u+at

a=-10m/s^2
t=4s
u=16m/s

hence v=-24m/s and as the question asks for speed and not velocity the answer is 24m/s
Why must people do this? I really don't understand it. Posting entire solutions helps no one. It's a waste of everyone's time.
12. I don't like doing it as the OP will not learn anything, but I just did this one as I didn't have time to take another example... and still don't have... but I'll give one anyway and might help the OP then...

A ball is thrown vertically upwards with a speed of 24.0m/s
(a) when is the velocity of the ball 12m/s? and what is the displacement?
(b) when is the velocity of the ball -12m/s? and what is the displacement?
(c) what is the velocity of the ball 1.50 s after launch?
(d) what is the maximum height reached by the ball?

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