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# differentiate (sec x)^2 watch

1. How would I do it? Cheers.
2. use the chain rule:
d/dx = 2(sec x). (sec x.tan x) since d(sec x)/dx = sec x.tan x
= 2(sec^2 x)(tan x)
3. Cheers! Doing Maclaurins, and trying to work out the series for tan (x). Foun
f(x)=x+1/3 x + 2/15 x^2 but that doesn't help too much as I need to find a lot more terms, so does anyone know how the coefficients are worked out?
4. Ok I just realised I meant tanh(x) and not tan(x).... oops. It's ok though.
5. hey how do you differentiate (secx)^5
6. (Original post by glasses)
hey how do you differentiate (secx)^5
In the same way

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