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differentiate (sec x)^2

barry_4_england

How would I do it? Cheers.

Reply 1

xx007

use the chain rule:
d/dx = 2(sec x). (sec x.tan x) since d(sec x)/dx = sec x.tan x
= 2(sec^2 x)(tan x)

Reply 2

barry_4_england

Cheers! Doing Maclaurins, and trying to work out the series for tan (x). Foun
f(x)=x+1/3 x + 2/15 x^2 but that doesn't help too much as I need to find a lot more terms, so does anyone know how the coefficients are worked out?

Reply 3

barry_4_england

Ok I just realised I meant tanh(x) and not tan(x).... oops :s-smilie:

. It's ok though.

Reply 4

glasses

hey how do you differentiate (secx)^5

Reply 5

TenOfThem

Original post by glasses

hey how do you differentiate (secx)^5

In the same way

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differentiate (sec x)^2

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