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    How would I do it? Cheers.
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    use the chain rule:
    d/dx = 2(sec x). (sec x.tan x) since d(sec x)/dx = sec x.tan x
    = 2(sec^2 x)(tan x)
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    Cheers! Doing Maclaurins, and trying to work out the series for tan (x). Foun
    f(x)=x+1/3 x + 2/15 x^2 but that doesn't help too much as I need to find a lot more terms, so does anyone know how the coefficients are worked out?
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    Ok I just realised I meant tanh(x) and not tan(x).... oops. It's ok though.
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    hey how do you differentiate (secx)^5
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    (Original post by glasses)
    hey how do you differentiate (secx)^5
    In the same way
 
 
 
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