Original post by esha06
I’m tryna do this question but i don’t know where to go from here
Original post by esha06
Image isnt showing for me.
Original post by mqb2766
Image isnt showing for me.
Image isnt showing for me.
Does this link work
https://share.icloud.com/photos/0c0tnI9hLD4nV4XJz_axY0Oww
Original post by esha06
Id have taken
u = tan(x)
as youve the sec^2 multiplied by it. Then maybe a second sub for the sqrt.
(edited 2 months ago)
Original post by mqb2766
They gave me the u as 1+tanx
Original post by esha06
Id have taken
u = tan(x)
as youve the sec^2 multiplied by it.
u = tan(x)
as youve the sec^2 multiplied by it.
They gave me the u as 1+tanx
Basically the same (without the second sub). You had u^2 = 1+tan. Id agree with u=tan+1
Original post by esha06
Id have taken
u = tan(x)
as youve the sec^2 multiplied by it.
u = tan(x)
as youve the sec^2 multiplied by it.
They gave me the u as 1+tanx
Note if youd done (properly)
u^2 = 1+tan(x)
then you get
2 u du = sec^2(x) dx
so your integrand becomes
2 u^2 (u^2-1) du
which is basically the same as the u=1+tan substitution.
(edited 2 months ago)
Original post by mqb2766
They gave me the u as 1+tanx
Original post by esha06
Id have taken
u = tan(x)
as youve the sec^2 multiplied by it.
u = tan(x)
as youve the sec^2 multiplied by it.
They gave me the u as 1+tanx
Note if youd done (properly)
u^2 = 1+tan(x)
then you get
2 u du = sec^2(x) dx
so your integrand becomes
2 u^2 (u^2-1) du
which is basically the same as the u=1+tan substitution.
Ohhhh i think i get it thank u
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