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OCR PHYSICS B G494~ 11th June 2015 AM ~ A2 Physics

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Original post by Mars256
I said that another cable could be attached at the bottom to it swinging. What did everyone put for it being unpractical to damp the lift?


I said that the lift needs to be able to 'oscillate' as that's it's function - to move up and down. Damping it would make energy transfers really inefficient so a lot of energy would be required to move it up and down.

Could be utterly wrong though.
Original post by james-aitken
For the number of collisions per second question, did you have to estimate a value for the collision time to work out the force per particle?


Pressure is Force/area so Force = pressure x are. Force is rate of change of momentum (mv/t). Rearrange to work out delta T is you know mass and velocity.

Then frequency is 1/T
I wrote adding a damper would require a huge mass that would make the building too top-heavy.
Original post by Rhetorical Hips
Can anyone remember the value they got for epsilon and the two capcitance questions? Epsilon was a tiny number, 10^-20 I think, while the first capacitance value was something like 10-2 Farads and the second was like 20 to 40 microfarads?


Got like 3.96x10^-20 for epsilon. Anyone else get 0.94uA for current leakage?
For the rate of collision one, I rearranged to find F, then found F exerted per particle by using change in momentum over time equals force, assuming that t=1 second. Then divided F by F exerted per particle. Bit of a messy method I know.
Original post by Minecraft27
I wrote adding a damper would require a huge mass that would make the building too top-heavy.

I put that it would require the cable to be buffered or something along those lines and then I couldn't coil around motor?
Anyone doing an unofficial markscheme?
Original post by Lewis7253
Got like 3.96x10^-20 for epsilon. Anyone else get 0.94uA for current leakage?


How did you work out current leakage? I rearranged C=Q/V to get inital current and final current, then divide change in current over time (60 seconds). I think it came out in the order of 10^-5 Farads and thus 10^1 microfarads.
Why couldn't we have attached the lift to something at the bottom?


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Reply 109
Original post by Lewis7253
Did anyone else do the actuvation energy one. Was tricky. Required natural logs and complex rearring. Think i got something like 3.96x10^-20J


I got that! Joke that it was a 2 marker - I saw an almost identical question in a past paper that was a 4 marker!
Original post by Rhetorical Hips
How did you work out current leakage? I rearranged C=Q/V to get inital current and final current, then divide change in current over time (60 seconds). I think it came out in the order of 10^-5 Farads and thus 10^1 microfarads.


Badsically the same way. Did V/t to get volts per second then used Q=CV to get charge per second which is current was like 9.4x10^-7A of 0.94uA
Original post by Rhetorical Hips
How did you work out current leakage? I rearranged C=Q/V to get inital current and final current, then divide change in current over time (60 seconds). I think it came out in the order of 10^-5 Farads and thus 10^1 microfarads.


I got 0.94


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Reply 112
Original post by Lewis7253
Got like 3.96x10^-20 for epsilon. Anyone else get 0.94uA for current leakage?


I got both of those!

Dropped 4 or 5 marks by running out of time :frown: expecting 41-43 to be an A
Original post by urz13
I got that! Joke that it was a 2 marker - I saw an almost identical question in a past paper that was a 4 marker!


Yeah I was worried I was on the wrong track when I notice it was only 2 marks for all that work!
Reply 114
Original post by Rhetorical Hips
How did you work out current leakage? I rearranged C=Q/V to get inital current and final current, then divide change in current over time (60 seconds). I think it came out in the order of 10^-5 Farads and thus 10^1 microfarads.

It was using dQ/dt. Find Q when V=0.12 and then dt=60s giving an answer of 0.94uA, I believe
Original post by Lewis7253
Badsically the same way. Did V/t to get volts per second then used Q=CV to get charge per second which is current was like 9.4x10^-7A of 0.94uA


Darn I must've got that one wrong then :frown:
what the actual **** was that section B, I got all the higher mark questions fine, but ironically left like four 2 markers.

What was that work out the mass of the Earth from R and density question all about?
Reply 117
Thoughts on A* boundary? I'd estimate about 47-49. Depends how many finished the paper as I found it very time consuming, many people in my school missed the entire last question due to running out of time.
Original post by ZestyX0r
what the actual **** was that section B, I got all the higher mark questions fine, but ironically left like four 2 markers.

What was that work out the mass of the Earth from R and density question all about?


Density=Mass/Volume therefore Mass=Density x Volume, you were given a rough estimate of density and volume=4/3 x pi x radius cubed

EDIT on the topic of that question, what reason did you guys give for G being to large?
Original post by urz13
Thoughts on A* boundary? I'd estimate about 47-49. Depends how many finished the paper as I found it very time consuming, many people in my school missed the entire last question due to running out of time.


Really?
I didn't find that


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