Hi so I have an equation which I am asked to differentiate ye^-2x=2x+y^2 I know the first bit is a product (I think that's what it's called) where I have to make it uv then use udv + vdu but then I have something that looks like this:
(-2ye^-2x+e^-2x)Dy/dx=2dx + 2ydy
And I don't know how to amalgamate the dys and dxs ... I hope this makes sense... Thanx
Hi so I have an equation which I am asked to differentiate ye^-2x=2x+y^2 I know the first bit is a product (I think that's what it's called) where I have to make it uv then use udv + vdu but then I have something that looks like this:
(-2ye^-2x+e^-2x)Dy/dx=2dx + 2ydy
And I don't know how to amalgamate the dys and dxs ... I hope this makes sense... Thanx
For the first half of the equation I have (y*e^-2x*-2+e^-2x*1)which is the dy/dx of ye^-2x then for the second half I have 2dx + 2ydy differentiating each term with respect to x/y... It's just that now I have one part of the equation with dy/dx and the other separate dx and dy
For the first half of the equation I have (y*e^-2x*-2+e^-2x*1)which is the dy/dx of ye^-2x then for the second half I have 2dx + 2ydy differentiating each term with respect to x/y... It's just that now I have one part of the equation with dy/dx and the other separate dx and dy
I see...well you're close with the LHS. You have the product rule and implicit differentiation. But dy/dx is not supposed to be multiplied by each term. On the RHS, I'm not sure how you have what you have. When you differentiate a function of x with respect to x, you don't have a dy/dx.
It might be helpful to review the topics.
But I'll start you of If ye−2x=2x+y2, then y×dxd(e−2x)+e−2x×dxdy=2+dxdy2
I see...well you're close with the LHS. You have the product rule and implicit differentiation. But dy/dx is not supposed to be multiplied by each term. On the RHS, I'm not sure how you have what you have. When you differentiate a function of x with respect to x, you don't have a dy/dx.
It might be helpful to review the topics.
But I'll start you of If ye−2x=2x+y2, then y×dxd(e−2x)+e−2x×dxdy=2+dxdy2
x=yn1=nyn−1dxdy
hey, how on earth did you write in 'equation'..? o.0