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# C1 Question help please! watch

1. HI there i was stuck on these two question because i have not learnt them so could someone please help me so i could note on how to do it

Q1 : x^5 + 1/ x^2 , write in the form x^p + x^q , where p and q are integers

Q2: The two curves y= 5 X 4 ^x and y=4^-x intersect at the point p
Show that the x-coordinates of the point p is a root of the equation 4^2x=0.2

Many thanks everyone!
2. for the first one its x to the power of 5 plus x to the power of minus 2
3. (Original post by amahmoud0129)
HI there i was stuck on these two question because i have not learnt them so could someone please help me so i could note on how to do it

Q1 : x^5 + 1/ x^2 , write in the form x^p + x^q , where p and q are integers

Q2: The two curves y= 5 X 4 ^x and y=4^-x intersect at the point p
Show that the x-coordinates of the point p is a root of the equation 4^2x=0.2

Many thanks everyone!

For the first one:

1/x^2 is the same as 1* x^-2 so x^-2
So you get x^5 + x^-2

For b is that 5 times 4^-x ?
4. (Original post by Dinaa)
For the first one:

1/x^2 is the same as 1* x^-2 so x^-2
So you get x^5 + x^-2

For b is that 5 times 4^-x ?
Hi y= 5 times 4^x and Y= 4 to the power -x
5. (Original post by amahmoud0129)
Hi y= 5 times 4^x and Y= 4 to the power -x
Since they intersect and we're looking for the x coordinate, you equal both equal equations together so the y's cancel.

5(4^x)=4^-x

Multiply by (4^x) obviously both sides

5(4^x)(4^x)=(4^-x)(4^x)

Using the indices rule:

5(4^2x)= 4^0

Anything to the power of 0 = 1

5(4^2x)= 1

Divide by 5

4^2x = 0.2

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Updated: January 31, 2016
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