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C1 Question help please!

HI there i was stuck on these two question because i have not learnt them so could someone please help me so i could note on how to do it

Q1 : x^5 + 1/ x^2 , write in the form x^p + x^q , where p and q are integers


Q2: The two curves y= 5 X 4 ^x and y=4^-x intersect at the point p
Show that the x-coordinates of the point p is a root of the equation 4^2x=0.2


Many thanks everyone!
for the first one its x to the power of 5 plus x to the power of minus 2
Reply 2
Original post by amahmoud0129
HI there i was stuck on these two question because i have not learnt them so could someone please help me so i could note on how to do it

Q1 : x^5 + 1/ x^2 , write in the form x^p + x^q , where p and q are integers


Q2: The two curves y= 5 X 4 ^x and y=4^-x intersect at the point p
Show that the x-coordinates of the point p is a root of the equation 4^2x=0.2


Many thanks everyone!



For the first one:

1/x^2 is the same as 1* x^-2 so x^-2
So you get x^5 + x^-2

For b is that 5 times 4^-x ?
Original post by Dinaa
For the first one:

1/x^2 is the same as 1* x^-2 so x^-2
So you get x^5 + x^-2

For b is that 5 times 4^-x ?


Hi y= 5 times 4^x and Y= 4 to the power -x
Reply 4
Original post by amahmoud0129
Hi y= 5 times 4^x and Y= 4 to the power -x


Since they intersect and we're looking for the x coordinate, you equal both equal equations together so the y's cancel.

5(4^x)=4^-x

Multiply by (4^x) obviously both sides

5(4^x)(4^x)=(4^-x)(4^x)

Using the indices rule:

5(4^2x)= 4^0

Anything to the power of 0 = 1

5(4^2x)= 1

Divide by 5

4^2x = 0.2

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