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Size:  461.8 KBAttachment 516171516173 Hi I am having trouble working these things out, I don't no if I put the right molecules in each place or what can someone tell me how to work these out in quite a simple form please
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    (Original post by robzpotter)
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Size:  461.8 KBAttachment 516171516173 Hi I am having trouble working these things out, I don't no if I put the right molecules in each place or what can someone tell me how to work these out in quite a simple form please
    so in the empty form below on the far left i put in 2C+3H2+0.5O2 in the right i put CH3CH2OH and in the bottom i put 2C+6H+O
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    (Original post by thefatone)
    so in the empty form below on the far left i put in 2C+3H2+0.5O2 in the right i put CH3CH2OH and in the bottom i put 2C+6H+O
    Thanks!

    But how do you then work it out?
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    (Original post by robzpotter)
    Thanks!

    But how do you then work it out?
    so you have enthalpy of combustion so arrows go from equation to elements at the bottom

    you have 2C and 3H2
    so you have 2(-393) and 3(-286)
    and the other arrow on the right you have -1368

    so now it's like vectors

    values of 2C and 3H2 - value of Ch3CH2OH
 
 
 

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