# Multiple choice As Physics AQA question Help needed.

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#1
A car exerts a driving force of 500N when travelling at a constant speed of 72 KMH-1 on a level track. What is the work done in 5 minutes??

According to the marksceme the answer is 2.0x10^5

Can someone explain how to get that that answer. Thanks !
0
6 years ago
#2
I don't get that answer, what I get is :-

Work done = Force * Distance.

Distance travelled = speed * time = 72 * (5/60) = 6km = 6000m

So, Work done - 500N * 6000m = 3x10^6 Nm

Is that what you've been getting?
1
6 years ago
#3
72 km h^-1 = 20 m s^-1

in 300 secs the car travels 6000 m

over that distance the car is exerting constant 500N force

work done = Fs

500 x 6000 = 3x10^6 J
1
6 years ago
#4
72KmH-1 = 20m/s

P=FV
20*500= 10,000W
PT=E
(5mins= 300 secs)
10,000*300= 3x10^6J
0
6 years ago
#5
fwiw MS says 3.0 x 10^6 J too

Q23 in paper http://filestore.aqa.org.uk/resource...081-SQP.PDF#24

answer to 23 is A (3.0 x 10^6 J)
in MS http://filestore.aqa.org.uk/resource...081-SMS.PDF#13
0
6 years ago
#6
I think you've been reading the wrong bit of the mark scheme Kraixo - the answer is A - 3x10^6J
0
4 years ago
#7
The mark scheme states that it is C 2.0*10^6 but when calculated it comes to 3.0*10^6 (A)
0
4 years ago
#8
When this specimen paper was first released, there were a couple of errors on the mark scheme, including this one. As others have pointed out, they have since put it right!
1
4 years ago
#9
I got this question from physics and maths tutor
0
4 years ago
#10
(Original post by MH1234567)
I got this question from physics and maths tutor
Very useful though that site is, the questions and marks schemes are largely just those from the exam boards. He has presumably put up the mark scheme that was released with the paper originally, rather than the corrected version.
0
4 years ago
#11
A car exerts a driving force of 500N when travelling at a constant speed of 72 KMH-1 on a level track. What is the work done in 5 minutes??

According to the marksceme the answer is 2.0x10^5

Can someone explain how to get that that answer. Thanks !
Distance = speed x time. Speed is in m/s so it is 72 x 10^3 / 3600. Now multiply that by 300 seconds which is the 5 minutes. Now W=fd (one of the few equations not given in formula sheet) so do 500 x the distance u got thats how its done
0
1 month ago
#12
was also confused by this, was sure my workings were correct, since then the mark scheme has not been updated. From what i see the answer is 3*10^6
0
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