Hey there! Sign in to join this conversationNew here? Join for free
    • Thread Starter
    Offline

    10
    ReputationRep:
    (Original post by RDKGames)
    Work out the area of the cross section first before multiplying it by 20 which is the depth of the prism.

    Any help on understanding this question please


    Posted from TSR Mobile
    Attached Images
      
    • Community Assistant
    • Welcome Squad
    Offline

    20
    ReputationRep:
    Community Assistant
    Welcome Squad
    (Original post by z_o_e)
    Any help on understanding this question please


    Posted from TSR Mobile
    25 litres is made up from orange juice, lemonade, and cranberry juice.

    To work out the amount of orange juice, work out 50% of 25 litres. To work out the amount of lemonade, work out \frac{2}{5} of 25 litres, etc...
    • Thread Starter
    Offline

    10
    ReputationRep:
    (Original post by RDKGames)
    25 litres is made up from orange juice, lemonade, and cranberry juice.

    To work out the amount of orange juice, work out 50% of 25 litres. To work out the amount of lemonade, work out \frac{2}{5} of 25 litres, etc...
    Thank you so much!!

    Posted from TSR Mobile
    • Thread Starter
    Offline

    10
    ReputationRep:
    Can someone help me on this please

    Posted from TSR Mobile
    Attached Images
     
    • Community Assistant
    • Study Helper
    Offline

    20
    ReputationRep:
    Community Assistant
    Study Helper
    (Original post by z_o_e)
    Can someone help me on this please

    Posted from TSR Mobile
    It's a 600ml bottle of remover and you mix a 1/4 of it with 4500ml water.

    So that means you mix 150ml remover with 4500ml water.

    So the ratio of remover to water must be 150:4500. Can you simplify this ratio?
    • Thread Starter
    Offline

    10
    ReputationRep:
    (Original post by notnek)
    It's a 600ml bottle of remover and you mix a 1/4 of it with 4500ml water.

    So that means you mix 150ml remover with 4500ml water.

    So the ratio of remover to water must be 150:4500. Can you simplify this ratio?
    30ml

    Posted from TSR Mobile
    • Thread Starter
    Offline

    10
    ReputationRep:
    Help on this would be appropriated

    Posted from TSR Mobile
    Attached Images
     
    • Community Assistant
    • Study Helper
    Offline

    20
    ReputationRep:
    Community Assistant
    Study Helper
    The ratio is 1:30 yes.

    So if you use 750ml of water, how much remover do you need?
    • Community Assistant
    • Study Helper
    Offline

    20
    ReputationRep:
    Community Assistant
    Study Helper
    (Original post by z_o_e)
    Help on this would be appropriated

    Posted from TSR Mobile
    Are those your lines on the diagram? They're correct and the lines on the left of the dot should be 1.5 times the length of the lines on the right of the dot.

    If you're unsure please explain why.
    • Thread Starter
    Offline

    10
    ReputationRep:
    (Original post by notnek)
    The ratio is 1:30 yes.

    So if you use 750ml of water, how much remover do you need?
    25

    Posted from TSR Mobile
    • Community Assistant
    • Study Helper
    Offline

    20
    ReputationRep:
    Community Assistant
    Study Helper
    That's correct.
    • Thread Starter
    Offline

    10
    ReputationRep:
    (Original post by notnek)
    Are those your lines on the diagram? They're correct and the lines on the left of the dot should be 1.5 times the length of the lines on the right of the dot.

    If you're unsure please explain why.
    I'm still stuck on the scale factor one. I don't know where to start from

    Posted from TSR Mobile
    • Community Assistant
    • Study Helper
    Offline

    20
    ReputationRep:
    Community Assistant
    Study Helper
    (Original post by z_o_e)
    I'm still stuck on the scale factor one. I don't know where to start from

    Posted from TSR Mobile
    Are those not your lines on the diagram? You start from the centre of enlargement which is the point drawn on your diagram.
    • Thread Starter
    Offline

    10
    ReputationRep:
    (Original post by notnek)
    Are those not your lines on the diagram? You start from the centre of enlargement which is the point drawn on your diagram.
    Yep and then count each square up till the centre and times it by -0.5

    Posted from TSR Mobile
    • Thread Starter
    Offline

    10
    ReputationRep:
    Can someone help me on this please


    Posted from TSR Mobile
    Attached Images
     
    Offline

    15
    ReputationRep:
    (Original post by z_o_e)
    Can someone help me on this please


    Posted from TSR Mobile
    You're finding the lowest common multiple of 5, 8 and 12 and then seeing how many packets you need of each candle so that you have the lowest common multiple number of each candle.
    Can you find the LCM?
    • Thread Starter
    Offline

    10
    ReputationRep:
    (Original post by B_9710)
    You're finding the lowest common multiple of 5, 8 and 12 and then seeing how many packets you need of each candle so that you have the lowest common multiple number of each candle.
    Can you find the LCM?
    Heya can you help me on this please

    Posted from TSR Mobile
    Attached Images
     
    • Community Assistant
    • Study Helper
    Offline

    20
    ReputationRep:
    Community Assistant
    Study Helper
    (Original post by z_o_e)
    Heya can you help me on this please

    Posted from TSR Mobile
    You need to write each surd in terms of \sqrt{2}.

    So for \sqrt{8}, you can write this as \sqrt{4 \times 2}

    And if you split up the root you get this

    \sqrt{4\times 2} = \sqrt{4} \times \sqrt{2} = 2 \sqrt{2}

    Have a go at the rest of the surds and please post your working if you get stuck.
    • Thread Starter
    Offline

    10
    ReputationRep:
    (Original post by notnek)
    You need to write each surd in terms of \sqrt{2}.

    So for \sqrt{8}, you can write this as \sqrt{4 \times 2}

    And if you split up the root you get this

    \sqrt{4\times 2} = \sqrt{4} \times \sqrt{2} = 2 \sqrt{2}

    Have a go at the rest of the surds and please post your working if you get stuck.
    I've done this so far

    Posted from TSR Mobile
    Attached Images
     
    • Community Assistant
    • Study Helper
    Offline

    20
    ReputationRep:
    Community Assistant
    Study Helper
    (Original post by z_o_e)
    I've done this so far

    Posted from TSR Mobile
    Now you just need to combine all the like terms. You can deal with surds similar to how you deal with letters in algebra so what's this:

    7x+6x-10x

    ?
 
 
 
  • See more of what you like on The Student Room

    You can personalise what you see on TSR. Tell us a little about yourself to get started.

  • Poll
    Brussels sprouts
    Useful resources

    Make your revision easier

    Maths

    Maths Forum posting guidelines

    Not sure where to post? Read the updated guidelines here

    Equations

    How to use LaTex

    Writing equations the easy way

    Student revising

    Study habits of A* students

    Top tips from students who have already aced their exams

    Study Planner

    Create your own Study Planner

    Never miss a deadline again

    Polling station sign

    Thinking about a maths degree?

    Chat with other maths applicants

    Can you help? Study help unanswered threads

    Groups associated with this forum:

    View associated groups
  • See more of what you like on The Student Room

    You can personalise what you see on TSR. Tell us a little about yourself to get started.

  • The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

    Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

    Quick reply
    Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.