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Algebra

IMG-20170401-WA0001.jpg Could someone help me with this? I'm pretty stuck :/
Original post by Sonechka
Could someone help me with this? I'm pretty stuck :/


Make tt the subject first from the second equation before substituting in for it into the first equation.
Reply 2
I would make a the subject of x
Then make t the subject of x
Sub them into the Y equation and simplify
Original post by zayn008
I would make a the subject of x
Then make t the subject of x
Sub them into the Y equation and simplify


That would still give an equation for yy in terms of x,t,ax,t,a
I've got y = -ax^2 - 12a^2x + 8a but I'm not sure how to get that into the form the question asks for. Should I substitute 2at^1/2 in for x and then go from there?
Original post by Sonechka
I've got y = -ax^2 - 12a^2x + 8a but I'm not sure how to get that into the form the question asks for. Should I substitute 2at^1/2 in for x and then go from there?


That's wrong, post your working.
Reply 6
Original post by RDKGames
That would still give an equation for yy in terms of x,t,ax,t,a


you could sub in tt in terms of x,ax, a again to remove the tt's from subbing in aa, but I'm guessing there's a better way
(edited 7 years ago)
Original post by zayn008
you could sub in tt in terms of x,ax, a again to remove the tt's from subbing in aa, but I'm guessing there's a better way


Yeah you're taking a needless step by substituting in for aa.

Just express tt in terms of x,ax,a and sub that in and simplify as there wouldn't be any tt terms any more
Original post by RDKGames
That's wrong, post your working.


I accidentally found 2at^2 instead of 2at and then didn't write 4a*a as 4a^2 :s :s

Would it be ax^2 - 4a^2x - 2ax + 8a^2? That doesn't look right either but...
Original post by Sonechka
I accidentally found 2at^2 instead of 2at and then didn't write 4a*a as 4a^2 :s :s

Would it be ax^2 - 4a^2x - 2ax + 8a^2? That doesn't look right either but...


That's wrong too. Post your working. You don't seem to be following what I've said in my first post...
Original post by RDKGames
That's wrong too. Post your working. You don't seem to be following what I've said in my first post...


t = x^2/4a^2
y = a(x^2/4a^2)^2 - 2a(x^2/4a^2)
= a(x^4/16a^4) - 2a(x^2/4a^2)
= ax^4/16a^5 - ax^2/4a^3

Is it ok up until there?
Original post by Sonechka
t = x^2/4a^2
y = a(x^2/4a^2)^2 - 2a(x^2/4a^2)
= a(x^4/16a^4) - 2a(x^2/4a^2)
= ax^4/16a^5 - ax^2/4a^3

Is it ok up until there?


Third line is fine, then your algebra mucks up. For example, ax416a4ax416a5\displaystyle a \cdot \frac{x^4}{16a^4} \neq \frac{ax^4}{16a^5} as you do not multiply the denominator by aa
Original post by RDKGames
Third line is fine, then your algebra mucks up. For example, ax416a4ax416a5a \cdot \frac{x^4}{16a^4} \neq \frac{ax^4}{16a^5} as you do not multiply the denominator by aa


Omg of course, what am I doing? Maybe doing maths at like half ten is a bad idea...

Anyway: ax^4/16a^4 - ax^2/2a^2?
Original post by Sonechka
Omg of course, what am I doing? Maybe doing maths at like half ten is a bad idea...

Anyway: ax^4/16a^4 - ax^2/2a^2?


Looks good. One small step and you got the required form.
Original post by RDKGames
Looks good. One small step and you got the required form.


So then I just cancel the as? x^4/16a^3 - x^2/2a?
Original post by Sonechka
So then I just cancel the as? x^4/16a^3 - x^2/2a?


Yes
Original post by RDKGames
Yes


Thanks so much! :smile:

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