OCR MEI S1 24th May 2017

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Original post by ExoIceCream99

No I got like 0.3 something.

How did you get that if you remember

I did 6 x (0.55 x 0.55 x 0.45 x 0.45 x 0.45) + (0.45 x 0.45 x 0.45) + 3 x (0.45 x 0.45 x 0.55 x 0.45), something like that

OP

Original post by ExoIceCream99

No I got like 0.3 something.

SAME
i loved the paper it was so nice
just couldnt do the 'atleast 2' question and the p(a|b) question but otherwise it was great!

For the Emily question I got 0.406 I think?

Original post by Dowel

I did 6 x (0.55 x 0.55 x 0.45 x 0.45 x 0.45) + (0.45 x 0.45 x 0.45) + 3 x (0.45 x 0.45 x 0.55 x 0.45), something like that

Ah I did 5 ****

Original post by Alex.trin

For the Emily question I got 0.406 I think?

I got that with the method I used

Original post by Dowel

I got that with the method I used

Yes! I used the same method as you, hopefully it's correct

What did everyone get for the students walk, bus etc. question about probability of 2 or more out of 4 students travelling using the same method?

Original post by a-spiringmedic

SAME
i loved the paper it was so nice
just couldnt do the 'atleast 2' question and the p(a|b) question but otherwise it was great!

Im pretty sure I got that at least 2 one wrong I put 0.9 something 😭

Original post by Aminah53

What did everyone get for the students walk, bus etc. question about probability of 2 or more out of 4 students travelling using the same method?

the answer was 1 - [(17C1 * 9C1 * 13C1 * 11C1)/(50C4)] as the probability of at least 2 people using the same mode of transport is the same as 1 - the probability they all use different modes of transport
this gives 1 - 21879/230300 which = 1- 0.095 = 0.905

For the cumulative frequency question did people add the 7 to the total?

(edited 6 years ago)

I did 24 x 17/50 x 9/49 x 13/48 x 11/47 and got 0.09500217108
then did 1 - that to get 0.90499 (0.905)

What do you guys think the grade boundaries will be like? I think it will be around 61 for an A, it was definitely a lot easier than last year's paper.

Original post by mxn

For the cumulative frequency question did people add the 7 to the total?

I don't think you were supposed to, but I could be wrong.

I did 1- (((17/50)*(9/49)*(13/48)*(11/47)) * (4!))And got the same answer (0.905)

Original post by mxn

For the cumulative frequency question did people add the 7 to the total?

I didn't, ****... i feel like you probably was supposed to since it was awkward numbers otherwise... rip

Having calculated lowest and highest bounds of results I'm hoping 93%- 100%

Someone said since they told us population levels for the entire year if you added 7 you got 365 days which makes sense

I thought the data for the 7 days was unknown though

What did everyone get for the expextation and variance question?

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