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jazz_xox_
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#1
In this question, the experiment is repeated with double volume- how would this affect the inital rate of reaction?
I have the concs of both reactants, value of K and the old initial rate of reaction
k=5.05 and other values listed in question. Thank you
(it's the second part of the question I'm stuck on)
I have the concs of both reactants, value of K and the old initial rate of reaction
k=5.05 and other values listed in question. Thank you

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#2
(Original post by jazz_xox_)
In this question, the experiment is repeated with double volume- how would this affect the inital rate of reaction?
I have the concs of both reactants, value of K and the old initial rate of reaction
k=5.05 and other values listed in question. Thank you
(it's the second part of the question I'm stuck on)
In this question, the experiment is repeated with double volume- how would this affect the inital rate of reaction?
I have the concs of both reactants, value of K and the old initial rate of reaction
k=5.05 and other values listed in question. Thank you

Repeat the experiment with different starting concentrations and the rate of reaction will be different too - it must be if you look at the rate equation for this reaction.
If you double the volume using just solvent, you will halve the concentrations of C and D. Work those concentrations out and put those values in the rate equation. K will be unchanged as the temperature will be the same in the repeated experiment.
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(Original post by TutorsChemistry)
The rate of reaction (initial or not) depends upon the concentration of reactants C and D, hence their concentrations are shown in the rate equation.
Repeat the experiment with different starting concentrations and the rate of reaction will be different too - it must be if you look at the rate equation for this reaction.
If you double the volume using just solvent, you will halve the concentrations of C and D. Work those concentrations out and put those values in the rate equation. K will be unchanged as the temperature will be the same in the repeated experiment.
The rate of reaction (initial or not) depends upon the concentration of reactants C and D, hence their concentrations are shown in the rate equation.
Repeat the experiment with different starting concentrations and the rate of reaction will be different too - it must be if you look at the rate equation for this reaction.
If you double the volume using just solvent, you will halve the concentrations of C and D. Work those concentrations out and put those values in the rate equation. K will be unchanged as the temperature will be the same in the repeated experiment.
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#4
(Original post by jazz_xox_)
Ahh thank you, I have the answer now- I was doubling the concentrations rather than halving them. Could you explain a bit more as to why doubling the volume halves the concentration.. is it to do with concentration = moles / volume.. so if the volume is 2 times as big it will cause the concentration to half?
Ahh thank you, I have the answer now- I was doubling the concentrations rather than halving them. Could you explain a bit more as to why doubling the volume halves the concentration.. is it to do with concentration = moles / volume.. so if the volume is 2 times as big it will cause the concentration to half?

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#6
(Original post by jazz_xox_)
Thank you so much! Do you have a website or any other resources by any chance
Thank you so much! Do you have a website or any other resources by any chance

It is very early days and I haven't published about rates yet. So far there are lessons on acids & bases, the pH scale, how to use the ionic product of water. Shortly I will publish about Ka for acids, then Ka for acidic buffers.
Many more topics will follow; eqilibrium and reaction rates are coming soon.
You can register and use for free at http://alevelchemistrytuition.co.uk/sign-up/
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#7
(Original post by TutorsChemistry)
Well, yes I have very recently started an A Level chemistry website. The plan is to cover each topic in the A level chemistry syllabuses.
It is very early days and I haven't published about rates yet. So far there are lessons on acids & bases, the pH scale, how to use the ionic product of water. Shortly I will publish about Ka for acids, then Ka for acidic buffers.
Many more topics will follow; eqilibrium and reaction rates are coming soon.
You can register and use for free at http://alevelchemistrytuition.co.uk/sign-up/
Well, yes I have very recently started an A Level chemistry website. The plan is to cover each topic in the A level chemistry syllabuses.
It is very early days and I haven't published about rates yet. So far there are lessons on acids & bases, the pH scale, how to use the ionic product of water. Shortly I will publish about Ka for acids, then Ka for acidic buffers.
Many more topics will follow; eqilibrium and reaction rates are coming soon.
You can register and use for free at http://alevelchemistrytuition.co.uk/sign-up/

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