In a 200cm^3 container, a certain amount of O2 is held within a piston at equilibrium with external pressure being 1 bar. The temperature of the gas is 298K. When 2J of heat is supplies, the gas expands against a constant external pressure. Assuming there is no heat lost calculate the new volume occupied after expansion.
In a 200cm^3 container, a certain amount of O2 is held within a piston at equilibrium with external pressure being 1 bar. The temperature of the gas is 298K. When 2J of heat is supplies, the gas expands against a constant external pressure. Assuming there is no heat lost calculate the new volume occupied after expansion.
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So we have an isothermal process occuring, hence change in internal energy is 0. We conclude therefore that:
delta U = delta q - p(external) delta V 0 = q - p (external) delta V delta V = q/p = 2/(10^5) m^3